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3 years ago

Help please i need it asap

Physics

2 answers:

mojhsa [17]3 years ago

6 0

Answer:

Explanation:

B, because if u subtract the forces from each other the forward one outweights the other ones

7nadin3 [17]3 years ago

6 0

Answer:

C. The car is moving at a constant speed.

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It is desired to lay off certain horizontal distances for building layouts. The length of the tapes are not 100.00 ft. Determine

Elodia [21]

Answer:

725.44 by 180.11

Explanation:

If a 100-ft tape was used, the number of such tapes in 725 ft would be $\dfrac{725}{100}=7.25$

And in 180 ft would be $\dfrac{180}{100}=1.8$

The same number of tapes would be used for the incorrect tape to give the false dimension. This would be

$100.06\times7.25$ by $100.06\times1.8$ =

$725.44$ by $180.11$

6 0

3 years ago

A car displaced 45 north of east by 10km

Amanda [17]

Answer:

coooooooooooooooooool

Explanation:

hab a good day :)

5 0

3 years ago

Read 2 more answers

HELP I WILL GIVE YOU ALL MY POINTS OR ANYTHING JUST HELP ME PLS

tiny-mole [99]

Answer: B, they can land themselves now

Explanation:

6 0

3 years ago

A cyclist intends to cycle up a 7.70o hill whose vertical height is 126m. Assuming the mass of bicycle plus person is 75.0kg, ca

Ksivusya [100]

Answer:

92704.5 J

596.44737 N

Explanation:

m = Mass of person + bicycle = 75 kg

g = Acceleration due to gravity = 9.81 m/s²

h = Vertical height = 126 m

$\theta$ = Angle = 7.7°

d = Diameter = 0.388 m

Work done against gravity is given by

$P=mgh\\\Rightarrow P=75\times 9.81\times 126\\\Rightarrow P=92704.5\ J$

Work done is 92704.5 J

Force required is given by

$F=\dfrac{mgrsin\theta}{\pi d}\\\Rightarrow F=\dfrac{75\times 9.81\times sin7.7\times 5.12}{\pi\times 0.388}\\\Rightarrow F=596.44737\ N$

The force is 596.44737 N

7 0

3 years ago

Find the wavelength of a photon which has 500.0 eV of energy.

jekas [21]

Answer:

2.5 x 10⁻⁹ m

Explanation:

E = Energy of photon = 500 eV = 500 x 1.6 x 10⁻¹⁹ J

c = speed of photon = 3 x 10⁸ m/s

λ = wavelength of photon = ?

Energy of photon is given as

$E = \frac{hc}{\lambda }$

inserting the values

$500\times 1.6\times 10^{-19} = \frac{(6.63\times 10^{-34})(3\times 10^{8})}{\lambda }$

λ = 2.5 x 10⁻⁹ m

5 0

4 years ago