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Sholpan [36]
3 years ago
12

A grating with 400 lines per mm is illuminated with light of wavelength 600.0 nm. a Determine the angles at which maxima are obs

erved b Determine the largest order that can be seen with this grating and this wavelength
Physics
1 answer:
KatRina [158]3 years ago
5 0

Answer:

(a) angles of maxima = 13.9°, 28.7° , 46°, 73.7° on either side

b] largest order = 4

Explanation:

(a) for diffraction maxima,

sin \theta =m\times \lambda/d

Here, m is the order, \lambda is the wavelength, \theta  is the angle at which maxima occur, d is inter planar spacing.

And we know that lines per mm (N) is related with d as,

N=\frac{1}{d}

Given that the wavelength is,

\lambda=600.0 nm=600\times 10^{-9}m

And N=\frac{400 lines}{mm} \\N=\frac{400 lines}{10^{-3}m }

Now,

sin \theta =m\times \lambda\times N

Therefore,

sin \theta= m\times600\times 10^{-9} \times 400\times 10^{3}\\sin \theta=0.24m

Here, m can be 1,2,3,4 as sin theta has to be less than 1.

\theta = arcsin 0.24 , arcsin 0.48 , arcsin 0.72 , arcsin 0.96

Therefore, angles of maxima = 13.9°, 28.7° , 46°, 73.7° on either side

b] largest order = 4

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