The gravitational force between <em>m₁</em> and <em>m₂</em> has magnitude
while the gravitational force between <em>m₁</em> and <em>m₃</em> has magnitude
where <em>x</em> is measured in m.
The mass <em>m₁</em> is attracted to <em>m₂</em> in one direction, and attracted to <em>m₃</em> in the opposite direction such that <em>m₁</em> in equilibrium. So by Newton's second law, we have
Solve for <em>x</em> :
The solution with the negative square root is negative, so we throw it out. The other is the one we want,
Answer:No, the slope won't be too steep
Explanation:
Force is an external agency that causes a body to change its position while friction is a force that causes a body to slide over another. This force is called the frictional force (Ff). The force that causes a body to move is the moving force (Fm).
The slope will be too steep if the frictional force is greater than the moving force since the frictional force tends to oppose the moving force.
According to the explanation, we need to get Ff and compare with the moving force along the plane.
If Ff>Fm it means the slope will be too steep but if Ff<Fm, the slope won't be too steep and as such the body can easily be moved along the plane.
Resolving forces acting along the plane we have FmSintheta + Ff = Fm (FmSintheta and Ff are added because they act in the same direction along the plane)
Fm=50N, theta=5°
Imputing this into the formula to get Ff;
50sin5°+Ff =50
Ff= 50-50sin5°
Ff= 50-4.35
Ff= 45.65N
Since Ff<Fm, this means the slope is not too steep and as such the 30kg load can be moved along the plane easily.
Answer:d
Explanation:
It is good to extend your bare hand forward when you are getting ready to catch a fast-moving ball so you can pull your hand back, increasing the time to slow the ball thus decreasing the force.
While catching impulse is being transferred to hands imparting great force, lowering hand would increase the time so that average force decreases and chances to drop the ball also decreases.
