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3 years ago

Galileo’s most important contribution to astronomy was his

Physics

2 answers:

olchik [2.2K]3 years ago

6 0

The answer is D I just took the test.

ikadub [295]3 years ago

3 0

When Galileo got ahold of a little telescope ... no more than
a kid's toy today ... he soon turned it towards the night sky.
The story says that he was the first one to do that. Apparently
everyone else who had these things used them to look at their
neighbors' windows. Anyway, When Galileo looked at Jupiter,
he saw four tiny dots. As he watched them night after night, he
saw that the four dots always stayed with Jupiter, but got nearer
and farther from it. He eventually realized that they were small
bodies in orbit around Jupiter. And then ... because he was Galileo ...
he made the big intellectual jump: He reasoned that if there were
smaller bodies in orbit around Jupiter, then Jupiter and the other
planets might also be in orbit around something, and not necessarily
around the Earth. He understood this as evidence that the sun is
the center of the solar system.

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An inductor is connected to a 26.5 Hz power supply that produces a 41.2 V rms voltage. What minimum inductance is needed to keep

alexira [117]

Answer:

The minimum inductance needed is 2.78 H

Explanation:

Given;

frequency of the AC, f = 26.5 Hz

the root mean square voltage in the circuit, $V_{rms}$ = 41.2 V

the maximum current in the circuit, I₀ = 126 mA

The root mean square current is given by;

$I_{rms} = \frac{I_o}{\sqrt{2} } \\\\I_{rms} = \frac{126*10^{-3}}{\sqrt{2} }\\\\I_{rms} =0.0891 \ A$

The inductive reactance is given by;

$X_l = \frac{V_{rms}}{I_{rms}} \\\\X_l= \frac{41.2}{0.0891}\\\\X_l = 462.4 \ ohms$

The minimum inductance needed is given by;

$X_l = \omega L\\\\X_l = 2\pi fL\\\\L = \frac{X_l}{2\pi f}\\\\L = \frac{462.4}{2\pi *26.5}\\\\L = 2.78 \ H$

Therefore, the minimum inductance needed is 2.78 H

7 0

3 years ago

How do I solve Q.14 & Q.15

timurjin [86]

14-needle heading west
15-the strength of the current and the distance

6 0

3 years ago

What is the ratio of a 0.7 in circle in centimeters.

kifflom [539]

I believe it would be 4.4

4 0

3 years ago

An object of length 3.00 cm is inside a plastic block with index of refraction 1.40. If the object is viewed from directly above

Lilit [14]

The length of its image = $-3cm$

Given,

length of object, $h_o = 3 cm$

We know, for flat refracting surface,

Image distance = object distance

So,

magnification is = $-1$

length of the image,

$h_i = magnification * h_o\\\\h_i = -1 * 3 \\\\h_i = -3cm$

Here, negative sign means inverted image.

For more information on refraction, visit

brainly.com/question/14760207?referrer=searchResults

3 0

3 years ago

Which of the following statements are true?Check all that apply.-In a uniform electric field, the field lines are straight, para

TiliK225 [7]

Answer:

1-In a uniform electric field, the field lines are straight, parallel, and uniformly spaced this statement is true.

2-Electric field lines near positive point charges radiate outward. this statement is also true.

3-The electric force acting on a point charge is proportional to the magnitude of the point charge. this statement is true as well.

Explanation:

the electric field created by a point charge is defined by E=KQ/r^2 where k is constant, q is magnitude of charge and r is the distance away from the point charge so the electric filed is distance dependent and can not be constant at all distances.

electric field lines near a negative point charge are directed radially inward because negative charge attracts the field and is not clockwise.

6 0

3 years ago