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andreyandreev [35.5K]
3 years ago
11

In which situation are the individual molecules moving the fastest? A) in a bowl of hot soup B) in a glass of iced tea C) in a g

lass of tap water D) in a cup of boiling water\
Chemistry
2 answers:
Airida [17]3 years ago
5 0
<h2>Answer : Option D) In a cup of boiling water</h2><h3>Explanation :</h3>

The individual molecules of water while boiling will move fastest amongst the given choices. As the boiling of water will cause the liquid molecules to increase the intermolecular forces of attraction between molecules and get escaped into vapors. Here, there is a transformation of state that is about to occur from liquid to gaseous. Compared to other examples, where there are no change of state occurring.

tresset_1 [31]3 years ago
5 0

D) in a cup of boiling water

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Balance the following reaction in KOH (under basic conditions). What are the coefficients in for C3H8O2 and KMnO4 in the balance
GrogVix [38]

Answer:

Coefficient of C_3H_8O_2=3

Coefficient of KMnO_4=8

Explanation:

We are given that  a reaction in which C_3H_8O_2 reacts with KMnO_4

We have to find the coefficient of each reactants in balanced reaction

3C_3H_8O_2(aq)+8KMnO_4(aq)\rightarrow 3C_3H_2O_4K_2(aq)+8MnO_2(aq)+2KOH+8H_2O

Coefficient is defined the constant  value multiplied with a reactant in a reaction.

Coefficient of C_3H_8O_2=3

Coefficient of KMnO_4=8

Coefficient of C_3H_2O_4K_2=3

Coefficient of MnO_2=8

Coefficient of H_2O=8

Coefficient of KOH=2

Hence, Coefficient of C_3H_8O_2=3 and coefficient of KMnO_4=8

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3 years ago
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Answer:

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elena55 [62]
The reactant is what you begin with.
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3 0
3 years ago
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if one mole of calcium carbonate (the limiting reactant) is used, how much calcium chloride should the reaction produce? look at
salantis [7]

Answer:

The answer to your question is <u>111 g of CaCl₂</u>

Explanation:

Reaction

                 2HCl  +  CaCO₃   ⇒    CaCl₂  +  CO₂  +  H₂O

Process

1.- Calculate the molecular mass of Calcium carbonate and calcium chloride

CaCO₃ = (1 x 40) + (1 x 12) + ((16 x 3) = 100 g

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Then 111g of CaCl₂ will be produced.

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