2.82 inches is are equivalent to 7.16 cm.
The volume of the cube ;
7.16 × 7.16 × 7.16 = 367.06 cm³
The density of titanium is 4.5 g/cm³
Therefore; mass will be 4.5 × 367.06 = 1651.77 g
1 mole of titanium has 47.867 g
thus, 1651.77 g is equivalent to 1651.77/ 47.867 = 34.507 moles
According to the Avagadro's constant 1 mole = 6.022 × 10∧23 atoms
Therefore, we get 6.022 × 10∧23 × 34.507 = 2.078 ×10∧25 atoms
Answer:
Certain things we think of as hard work, such as writing an exam or carrying a heavy load on level ground, are not work as defined by a scientist. The scientific definition of work reveals its relationship to energy—whenever work is done, energy is transferred.
For work, in the scientific sense, to be done, a force must be exerted and there must be motion or displacement in the direction of the force.
Newton's second law of motion can be formally stated as follows:
The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.
This verbal statement can be expressed in equation form as follows:
a = Fnet / m
<span>The best reason I can think of for why we believe that air is a mixture is that freezing air slowly yields different liquids at different temperatures. Liquid nitrogen has a different boiling point than liquid oxygen. They also freeze at different temperatures. If air were only 1 compound, then air in its entirety would have a single boiling point and a single freezing point. </span>
<span> are composed of the fragments, or CLASTS. If PRE-existing </span>minerals<span> and rock. A </span>clast<span> is a fragment of </span>geological detritus,<span>chunks and smaller grains of rock broken off other rocks by </span>physical weathering.[2]<span> Geologists use the term CLASTIC </span><span>with reference to </span>sedimentary rocks<span> as well as to particles in </span>sediment transport<span> whether in </span>suspension<span> or as </span>bed load<span>, and in </span>sediment<span> deposits.</span>
