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Kitty [74]
4 years ago
13

Identify the process in which the entropy increases. Identify the process in which the entropy increases. the phase transition f

rom a solid to a gas a decrease in the number of moles of a gas during a chemical reaction the phase transition from a liquid to a solid the phase transition from a gas to a liquid the phase transition from a gas to a solid
Chemistry
1 answer:
diamong [38]4 years ago
7 0

Answer:

The phase transition from a solid to a gas.

Explanation:

Entropy is related to the moles of gases available. The more gaseous moles, the higher the entropy.

<em>Identify the process in which the entropy increases.</em>

  • <em>the phase transition from a solid to a gas</em>. YES. There are more gaseous moles available so entropy increases.
  • <em>a decrease in the number of moles of a gas during a chemical reaction</em>. NO. This causes a decrease in entropy.
  • <em>the phase transition from a liquid to a solid</em>. NO. There is almost no change in the entropy in this process.
  • <em>the phase transition from a gas to a liquid</em>. NO. There is a decrease in entropy in this process.
  • <em>the phase transition from a gas to a solid</em>. NO. There is a decrease in entropy in this process.
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8 0
2 years ago
What is the atomic mass number of an isotope that has an atomic number of 5 and includes 6 neutrons?
irinina [24]

The answer should be; 11

The atomic mass number is found by combining the number of protons and neutrons

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8 0
3 years ago
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zlopas [31]

Answer:

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Explanation:

7 0
3 years ago
For the reaction 2 H2S(g) D 2 H2 (g) + S2 (g), Kp = 1.5 × 10−5 at 800.0°C. If the initial partial pressures of H2 and S2 in a cl
Usimov [2.4K]

Answer: The approximate equilibrium partial pressure of H_2S is 3.92  atm

Explanation:

Equilibrium constant is the ratio of the concentration of products to the concentration of reactants each term raised to its stochiometric coefficients.

The given balanced equilibrium reaction is,

      2H_2S(g)\rightleftharpoons 2H_2(g)+S_2(g)

K_p=\frac{[H_2]^2\times [S_2]}{[H_2S]^2}

1.5\times 10^{-5}=\frac{[H_2]^2\times [S_2]}{[H_2S]^2}

On reversing the reaction:

     2H_2(g)+S_2(g)\rightleftharpoons 2H_2S(g)

initial pressure  4.00atm    2.00 atm       0

eqm          (4.00-2x)atm      (2.00-x) atm      2x atm

K_p=\frac{[H_2S]^2}{[H_2]^2\times [S_2]}

K_p'=\frac{1}{K_p}=0.67\times 10^5

2H_2(g)+S_2(g)\rightleftharpoons 2H_2S(g)

0.67\times 10^5=\frac{2x]^2}{[4.00-2x]^2\times [2.00-x]}

x=1.96

[H_2S]=2x=2\times 1.96=3.92 atm

Thus approximate equilibrium partial pressure of H_2S is 3.92 atm

3 0
3 years ago
How do you find mass in a balanced chemical equation help pleaseeee
oksano4ka [1.4K]
Chemists use balanced chemical equations as a basis to calculate how much reactant is needed or how much product will be formed in a reaction.
4 0
3 years ago
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