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Viefleur [7K]
2 years ago
14

Assuming the incline to be frictionless and the zero of gravitational potential energy to be at the elevation of the horizontal

line, Group of answer choices the kinetic energy of the block when it has fully compressed the spring will be the kinetic energy of the block just before it collides with the spring will be equal to mgh. the kinetic energy of the block when it has fully compressed the spring will be equal to mgh. the kinetic energy of the block when it has fully compressed the spring will be zero. the kinetic energy of the block just before it collides with the spring will be kx2. Not saved Questions AnsweredQuestion 1 AnsweredQuestion 2 AnsweredQuestion 3 AnsweredQuestion 4 AnsweredQuestion 5 AnsweredQuestion 6 AnsweredQuestion 7 AnsweredQuestion 8 AnsweredQuestion 9 Haven't Answered YetQuestion 10 Time Elapsed: Hide Attempt due: Oct 12 at 11:59pm
Physics
1 answer:
Leya [2.2K]2 years ago
4 0

The energy in the system is given by the law of conservation of energy.

The energy stored in the spring plus the gravitational potential energy of the block when it has fully compressed the spring will be equal to m·g·h.

Reason:

The given parameters are;

Surface of the inclined plane = Frictionless

Potential energy at the horizontal line = Zero of gravitational potential

By the law of Conservation of Energy, we have;

The spring will be compressed by a distance, <em>x</em>

The energy stored in the compressed spring, K.E. = (1/2)·k·x²

Energy in the block when the block comes to rest at a height, h₁, will be, P.E. = m·g·h₁

Therefore, by conservation of energy, we have;

The initial potential of the block = The stored energy in the compressed string + The gravitational potential energy of the block when it has compressed.

Therefore, the correct option is; <u>The energy stored in the spring plus the gravitational potential energy of the block when it has fully compressed the spring will be equal to m·g·h</u>

Learn more here;

brainly.com/question/17713698

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When a current is passed through plasma and that current is increased will the temperature of the plasma increase . if it does t
Delicious77 [7]

The temperature of the plasma will increase as current is passed through it.

<h3>Meaning of Current and temperature</h3>

Current can be defined as a flow of charged particles through a medium and the particles includes: electrons or ions.

Temperature is the degree of hotness or coldness experienced by a material.

The more current passes through the plasma the more energy is induced making the particles to move faster which in turns causes temperature to increase and reducing the resistance of the plasma.

In conclusion, The current causes temperature to increase and this reduces the resistance.

Learn more about current: brainly.com/question/1100341

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6 0
2 years ago
When a solid is placed in a container and heat is applied, a phase change occurs. Watch the video and identify which of the foll
goldenfox [79]

Answer:

a) false b) true c) true d) false and e) true

Explanation:

a) false.   All the energy applied is used for the phase change, so the temperature remains constant.

b)   true.   The kinetic energy is associated with the speed of the particles and they have more mobility in the liquid, therefore, more kinetic energy.

c)   true.   Since energy is used for state change

d)  false.   In general, mobility and temperature are proportional

e)  true.  Heat is the source of energy for the change of state

4 0
3 years ago
Read 2 more answers
The parallel plates in a capacitor, with a plate area of 7.90 cm2 and an air-filled separation of 2.70 mm, are charged by a 7.90
s2008m [1.1K]

Answer:

A) 26V

Explanation:

(a) the potential difference between the plates

Initial capacitance can be calculated using below expresion

C1= A ε0/ d1

Where d1= distance between = 2.70 mm= 2.70× 10^-3 m

ε0= permittivity of space= 8.85× 10^-12 Fm^-1

A= area of the plate = 7.90 cm2 = 7.90 ×10^-4 m^2

If we substitute the values we

C1= A ε0/ d1

=( 7.90 ×10^-4 × 8.85× 10^-12 )/2.70× 10^-3

C1=2.589 ×10^-12 F= 2.59 pF

Initial charge can be determined using below expresion

q1= C1 × V1

V1=2.589 ×10^-12 F

V1= voltage=7.90 V

If we substitute we have

q1= 2.589 ×10^-12 × 7.90

q1= 20.45×10^-12C

20.45 pC

Final capacitance can be calculated as

C2= A ε0/ d2

d2=8.80 mm= /8.80× 10^-3

7.90 ×10^-4 × 8.85× 10^-12 )/8.80× 10^-3

C1=0.794 ×10^-12 F= 0.794 pF

Final charge= initial charge

q2=q1 (since the battery is disconnected)

q2=q1= 20.45 pC

Final potential difference

V2= q/C2

= 20.45/0.794

= 26V

6 0
3 years ago
An​ airplane, flying horizontally at an altitude of 3 miles​, passes directly over an observer. If the constant speed of the air
natima [27]
I’m not sure if this helped you so here you go

6 0
3 years ago
A beam of light traveling through a liquid (of index of refraction n1 = 1.47) is incident on a surface at an angle of θ1 = 59° w
frosja888 [35]

Answer:

(a) n_{2} = \frac{n_{1}sin\theta_{1}}{sin\theta_{2}}

(b) n_{2} = 1.349

(c) v_{1} = 2.04\times 10^{8}\ m/s

(d) v_{2} = 2.22\times 10^{8}\ m/s

Solution:

As per the question:

Refractive index of medium 1, n_{1} = 1.47

Angle of refraction for medium 1, \theta_{1} = 59^{\circ}

Angle of refraction for medium 2, \theta_{1} = 69^{\circ}

Now,

(a) The expression for the refractive index of medium 2 is given by using Snell's law:

n_{1}sin\theta_{1} = n_{2}sin\theta_{2}

where

n_{2} = Refractive Index of medium 2

Now,

n_{2} = \frac{n_{1}sin\theta_{1}}{sin\theta_{2}}

(b) The refractive index of medium 2 can be calculated by using the expression in part (a) as:

n_{2} = \frac{1.47\times sin59^{\circ}}{sin69^{\circ}}

n_{2} = 1.349

(c) To calculate the velocity of light in medium 1:

We know that:

Refractive\ index,\ n = \frac{Speed\ of\ light\ in vacuum,\ c}{Speed\ of\ light\ in\ medium,\ v}

Thus for medium 1

n_{1} = \frac{c}{v_{1}

v_{1} = \frac{c}{n_{1} = \frac{3\times 10^{8}}{1.47} = 2.04\times 10^{8}\ m/s

(d) To calculate the velocity of light in medium 2:

For medium 2:

n_{2} = \frac{c}{v_{2}

v_{2} = \frac{c}{n_{1} = \frac{3\times 10^{8}}{1.349} = 2.22\times 10^{8}\ m/s

5 0
3 years ago
Read 2 more answers
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