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2 years ago

A(n) ____________ is a high energy electron released from a nucleus during radioactive decay.

Chemistry

1 answer:

jonny [76]2 years ago

4 0

Answer:

beta

Explanation:

A beta particle (symbol β) is a high-speed and high-energy electron which is emitted by radioactive decay of the atomic nucleus during process of the beta decay.

Strontium-90 is material which is most commonly used to produce the beta particles.

Beta particles are used to treat conditions such as eye as well as bone cancer.

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A. Identify the steps of the scientific method?

DedPeter [7]

Answer:

1. The steps of the scientific method consist of seven things: Ask a question, get the research needed for a experiment, (What are you trying to find out? What materials do I need to complete the experiment? What are the procedures needed to complete the experiment?) create a hypothesis, (your educated guess on what you think the results of the experiment will be) conduct a experiment (complete multiple different trials preferably three) to test your hypothesis, make observations and record data during the experiment, draw a conclusion, (Was your hypothesis correct? Yes or no and explain why it is wrong or right) present your findings.

2. A hypothesis is a educated guess that the scientist believe will be the answer at the end of the experiment which is why they conduct a experiment in the first place to find viable data that will support their hypothesis.

3. Predictions consist of theories that will test the hypothesis (educated guess) because they're the reasoning to why you believe your guess is correct.

4. A control group consists of variables that do not go through change during a experiment, things that remain the same.

5. Data can be presented in many different ways in the form of graphs, charts, or a research paper. You find the data by completing multiple different trials in a experiment, to make sure you have valid results to write down in your data research.

6. Remember that your hypothesis is your educated guess at the beginning of the experiment, what YOU thought was going to happen during the experiment and if the data you received during the experiment supports your hypothesis.

7. Your procedures, perhaps you measured a variable wrong, perhaps you used to much, or to little of a variable, all depends on your experiment.

8. Having people review and test your data by conducting their own experiments will not only make sure that your data is valid but it insures you even more of your conclusion, making it more accepted by other scientists.

Hope this helps.

4 0

2 years ago

Chameleons have the ability to change their coloring to help them blend in with their environmerit.

Andre45 [30]

Answer:

Explanation:

trust me

3 0

2 years ago

Read 2 more answers

A sample consisting of 1.00 mol of perfect gas molecules at 27 °C is expanded isothermally from an initial pressure of 3.00 atm

Evgesh-ka [11]

Answer:

a) reversibly

ΔU = 0

q = 2740.16 J

w = -2740.16 J

ΔH = 0

ΔS(total) = 0

ΔS(sys) =9.13 J/K

ΔS(surr) = -9.13 J/K

b) against a constant external pressure of 1.00 atm

ΔU = 0

w = -1.66 kJ

q = 1.66 kJ

ΔH = 0

ΔS(sys) = 9.13 J/K

ΔS(surr) = -5.543 J/K

ΔS(total) = 3.587 J/K

Explanation:

Step 1: Data given:

Number of moles = 1.00 mol

Temperature = 27.00 °C = 300 Kelvin

Initial pressure = 3.00 atm

Final pressure = 1.00 atm

The gas constant = 8.31 J/mol*K

(a) reversibly

Step 2: Calculate work done

For ideal gases ΔU depends only on temperature. So as it is an isothermal (T constant).

Since the temperature remains constant:

ΔU = 0

ΔU = q + w

q = -w

w = -nRT ln (Pi/Pf)

⇒ with n = the number of moles of perfect gas = 1.00 mol

⇒ with R = the gas constant = 8.314 J/mol*K

⇒ with T = the temperature = 300 Kelvin

⇒ with Pi = the initial pressure = 3.00 atm

⇒ with Pf = the final pressure = 1.00 atm

w =- 1*8.314 *300 * ln(3)

w = -2740.16 J

q = -w

q = 2740.16 J

Step 3: Calculate change in enthalpy

Since there is no change in energy, ΔH = 0

Step 4: Calculate ΔS

for an isothermal process

ΔS (total) = ΔS(sys) + ΔS(surr)

ΔS(sys) = -ΔS(surr)

ΔS(sys) = n*R*ln(pi/pf)

ΔS(sys) = 1.00 * 8.314 * ln(3)

ΔS(sys) = 9.13 J/K

ΔS(surr) = -9.13 J/K

ΔS (total) = ΔS(sys) + ΔS(surr) = 0

(b) against a constant external pressure of 1.00 atm

Step 1: Calculate the work done

w = -Pext*ΔV

w = -Pext*(Vf - Vi)

⇒ with Vf = the final volume

⇒ with Vi = the initial volume

We have to calculate the final and initial volume. We do this via the ideal gas law P*V=n*R*T

V = (n*R*T)/P

Initial volume = (n*R*T)/Pi

⇒ Vi = (1*0.08206 *300)/3

⇒ Vi = 8.206 L

Final volume = (n*R*T)/Pf

⇒ Vf = (1*0.08206 *300)/1

⇒ Vf = 24.618 L

The work done w = -Pext*(Vf - Vi)

w = -1.00* ( 24.618 - 8.206)

w = -16.412 atm*L

w = -16 .412 *(101325/1atm*L) *(1kJ/1000J)

w = -1662.9 J = -1.66 kJ

Step 2: Calculate the change in internal energy

ΔU = 0

q = -w

q = 1.66 kJ

ΔH = 0 because there is no change in energy

Step 3: Calculate ΔS

ΔS(sys) = n*R*ln(3)

ΔS(sys) = 1.00 * 8.314 * ln(3)

ΔS(sys) = 9.13 J/K

ΔS(surr) = -q/T

ΔS(surr) = -1662.9J/300K

ΔS(surr) = -5.543 J/K

ΔS(total) = ΔS(surr) +ΔS(sys) = -5.543 J/K + 9.13 J/K = 3.587 J/K

4 0

3 years ago

How many lone pairs are on the central atom of BrF3?

allochka39001 [22]

Answer:

BrF3 has 2 lone pairs (4 unshared electrons)

Explanation:

8 0

3 years ago

What volume will 75 g of O2 occupy at STP?

Nady [450]

p = latm

t = 273.15K

R= 0.08206 L atm mol K

75.0g02

16.00 (O₂) = 4.6875mol mol

Ideal gas law: PV = nRT, solve for volume: V = nRT P

V =

4.6875mol 0.08206 L-atm mol. K · 273.15K

V = 105L

latm

3 0

2 years ago