Answer:
83.20 g of Na3PO4
Explanation:
1 mole of Na3PO4 contains 3 moles of Na+.
Mole of Na ion to be prepared = Molarity x volume
= 0.700 x 725/1000
= 0.5075 mole
If 1 mole of Na3PO4 contains 3 moles of Na ion, then 0.5075 Na ion will be contained in:
0.5075/3 x 1 = 0.1692 mole of Na3PO4
mole of Na3PO4 = mass/molar mass = 0.1692
Hence, mass of Na3PO4 = 0.1692 x molar mass
= 0.1692 x 163.94
= 83.20 g.
83.20 g of Na3PO4 will be needed.
1s to the second power, 2s to the second power, 2p to the 6th power, 3s to the second power and 3p to the third power.
Answer:
is the total pressure of the tank.
Explanation:
Partial pressures of nitrogen = 
Partial pressure of oxygen = 
Total pressure of gases in the tank = P
Applying Dalton's law of partial pressures :


is the total pressure of the tank.
Explanation:
Below is an attachment containing the solution.
Answer:
True
Explanation:
The length of covalent bond depends upon the size of atoms and the bond order.