All categories

3 years ago

Which vector should be negative?

Physics

1 answer:

Ket [755]3 years ago

7 0

Answer: the velocity of a falling object.

As the object is falling down it is experiencing a velocity that is continuously reducing each second and becomes 0 once it reaches the ground. The graph between velocity and time in this case would be a negative slope.

Thus for a object falling down the velocity considered would be negative owing to the reducing speed.

You might be interested in

A crate is being pulled down an incline as shown in the figure. With respect to the crate's direction of motion, which of the fo

Dmitrij [34]

Answer: Fn

Explanation: Because Fn is applying force upward

7 0

3 years ago

Suppose your hair grows at the rate of 1/55 inch per day. Find the rate at which it grows in nanometers per second. Because the

qwelly [4]

Answer:5.35nm

Explanation:

Consider that 1 inch is = 0.0254m

we have,

1m= 1x10^9 nm

While:

0.0254m = 2.54x10^7nm

1/55 (2.54x10^7) = 4.6181 x 10^5nm

1 day= 24 hrs

= (24x60) when calculating in min

= (24x60x60) calculating in seconds we have:

= 8.64x10⁴sec

In 8.64x10^4 seconds, the hair grows by 4.6181 x 10^5nm

Therefore, the amount by which the hair grows in 1 second will be;

= (4.6181 x 10^5)/(8.64x10^4)

= 5.35nm

The rate of growth will be 5.35nm

7 0

3 years ago

a force 2.4E2 N exists between a positive charge of 8E-5 C and a positive charge of 3E-5 C. What distance separates the charges?

Verdich [7]

The distance between the two charges is $0.3 m$

Explanation:

The electrostatic force between two charged objects is given by Coulomb's law:

$F=k\frac{q_1 q_2}{r^2}$

where:

$k=8.99\cdot 10^9 Nm^{-2}C^{-2}$ is the Coulomb's constant

$q_1, q_2$ are the charges of the two objects

r is the separation between the two charges

In this problem, we are given the following:

$q_1 = 8\cdot 10^{-5} C$

$q_2 = 3\cdot 10^{-5} C$

$F=2.4\cdot 10^2 N$

Therefore, we can rearrange the equation to solve for r, the distance between the two charges:

$r=\sqrt{\frac{kq_1 q_2}{F}}=\sqrt{\frac{(8.99\cdot 10^9)(8\cdot 10^{-5})(3\cdot 10^{-5})}{2.4\cdot 10^2}}=0.3 m$

Learn more about electrostatic force:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

6 0

3 years ago

Jack and Jill are maneuvering a 3100 kg boat near a dock. Initially the boat's position is < 2, 0, 3 > m and its speed is

liraira [26]

Answer:

(a) work done by Jack is -2200J

(b) work done by Jill is 0

Explanation:

Given;

Initially boat's position = < 2, 0, 3 > m

Final boat's position = < 6, 0, 1 > m

change in position = < 4, 0, -2 >

Force exerted by Jack = < -440, 0, 220 > N

Force exerted by Jill = < 170, 0, 340 > N

Part (a) How much work does Jack do?

work done = force x distance

Jack's work = < -440, 0, 220 > N x < 4, 0, -2 > m

= [(-440*4) + (0*0) + (220*-2)]

= -1760 J - 440 J

= -2200J

Part (b) How much work does Jill do?

Jill's work = < 170, 0, 340 > N x < 4, 0, -2> m

= [(170*4) + (0*0) + (340*-2)]

= 680 J - 680 J

= 0

7 0

4 years ago

Use the diagram to answer each question.

HACTEHA [7]

At E the potential energy is maximum/highest. The potential energy decreases as it goes down and increases as it goes up. so if the pendulum swinged from E to A, potential energy would decrease till C and increase till A.

7 0

3 years ago