Answer:
The distance is 1.69 m.
Explanation:
Given that,
First charge ![q_{1}= 3.8\times10^{-6}\ C](https://tex.z-dn.net/?f=q_%7B1%7D%3D%203.8%5Ctimes10%5E%7B-6%7D%5C%20C)
Second charge ![q_{2}=3.2\times10^{-6}\ C](https://tex.z-dn.net/?f=q_%7B2%7D%3D3.2%5Ctimes10%5E%7B-6%7D%5C%20C)
Distance = 3.25 m
We need to calculate the distance
Using formula of electric field
![E_{1}=E_{2}](https://tex.z-dn.net/?f=E_%7B1%7D%3DE_%7B2%7D)
![\dfrac{kq_{1}}{x^2}=\dfrac{kq_{2}}{(d-x)^2}](https://tex.z-dn.net/?f=%5Cdfrac%7Bkq_%7B1%7D%7D%7Bx%5E2%7D%3D%5Cdfrac%7Bkq_%7B2%7D%7D%7B%28d-x%29%5E2%7D)
![\dfrac{q_{1}}{q_{2}}=\dfrac{(x)^2}{(d-x)^2}](https://tex.z-dn.net/?f=%5Cdfrac%7Bq_%7B1%7D%7D%7Bq_%7B2%7D%7D%3D%5Cdfrac%7B%28x%29%5E2%7D%7B%28d-x%29%5E2%7D)
![\sqrt{\dfrac{q_{1}}{q_{2}}}=\dfrac{x}{d-x}](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cdfrac%7Bq_%7B1%7D%7D%7Bq_%7B2%7D%7D%7D%3D%5Cdfrac%7Bx%7D%7Bd-x%7D)
![x=(d-x)\times\sqrt{\dfrac{q_{1}}{q_{2}}}](https://tex.z-dn.net/?f=x%3D%28d-x%29%5Ctimes%5Csqrt%7B%5Cdfrac%7Bq_%7B1%7D%7D%7Bq_%7B2%7D%7D%7D)
Put the value into the formula
![x=(3.25-x)\times\sqrt{\dfrac{3.8\times10^{-6}}{3.2\times10^{-6}}}](https://tex.z-dn.net/?f=x%3D%283.25-x%29%5Ctimes%5Csqrt%7B%5Cdfrac%7B3.8%5Ctimes10%5E%7B-6%7D%7D%7B3.2%5Ctimes10%5E%7B-6%7D%7D%7D)
![x+x\times\sqrt{\dfrac{3.8\times10^{-6}}{3.2\times10^{-6}}}=3.25\times\sqrt{\dfrac{3.8\times10^{-6}}{3.2\times10^{-6}}}](https://tex.z-dn.net/?f=x%2Bx%5Ctimes%5Csqrt%7B%5Cdfrac%7B3.8%5Ctimes10%5E%7B-6%7D%7D%7B3.2%5Ctimes10%5E%7B-6%7D%7D%7D%3D3.25%5Ctimes%5Csqrt%7B%5Cdfrac%7B3.8%5Ctimes10%5E%7B-6%7D%7D%7B3.2%5Ctimes10%5E%7B-6%7D%7D%7D)
![x(1+\sqrt{\dfrac{3.8\times10^{-6}}{3.2\times10^{-6}}})=3.25\times\sqrt{\dfrac{3.8\times10^{-6}}{3.2\times10^{-6}}}](https://tex.z-dn.net/?f=x%281%2B%5Csqrt%7B%5Cdfrac%7B3.8%5Ctimes10%5E%7B-6%7D%7D%7B3.2%5Ctimes10%5E%7B-6%7D%7D%7D%29%3D3.25%5Ctimes%5Csqrt%7B%5Cdfrac%7B3.8%5Ctimes10%5E%7B-6%7D%7D%7B3.2%5Ctimes10%5E%7B-6%7D%7D%7D)
![x=\dfrac{3.25\times\sqrt{\dfrac{3.8\times10^{-6}}{3.2\times10^{-6}}}}{(1+\sqrt{\dfrac{3.8\times10^{-6}}{3.2\times10^{-6}}})}](https://tex.z-dn.net/?f=x%3D%5Cdfrac%7B3.25%5Ctimes%5Csqrt%7B%5Cdfrac%7B3.8%5Ctimes10%5E%7B-6%7D%7D%7B3.2%5Ctimes10%5E%7B-6%7D%7D%7D%7D%7B%281%2B%5Csqrt%7B%5Cdfrac%7B3.8%5Ctimes10%5E%7B-6%7D%7D%7B3.2%5Ctimes10%5E%7B-6%7D%7D%7D%29%7D)
![x=1.69\ m](https://tex.z-dn.net/?f=x%3D1.69%5C%20m)
Hence, The distance is 1.69 m.
Answer:
![\Delta Q=-230kJ](https://tex.z-dn.net/?f=%5CDelta%20Q%3D-230kJ)
Explanation:
Using the first law of thermodynamics:
![\Delta U=\Delta Q-W](https://tex.z-dn.net/?f=%5CDelta%20U%3D%5CDelta%20Q-W)
Where
is the change in the internal energy of the system, in this case
,
is the heat tranferred, and
is the work,
with a negative sign since the work is done by the system.
From the previous equation we solve for heat, because it is the unknown variable in this problem
![\Delta Q=\Delta U +W](https://tex.z-dn.net/?f=%5CDelta%20Q%3D%5CDelta%20U%20%2BW)
And replacing the known values:
![\Delta Q=250kJ +(-480kJ)](https://tex.z-dn.net/?f=%5CDelta%20Q%3D250kJ%20%2B%28-480kJ%29)
![\Delta Q=250kJ -480kJ](https://tex.z-dn.net/?f=%5CDelta%20Q%3D250kJ%20-480kJ)
![\Delta Q=-230kJ](https://tex.z-dn.net/?f=%5CDelta%20Q%3D-230kJ)
The negative sign shows us that the heat is tranferred from the system into the surroundings.
Let's see: frequency of cellular phone waves (GSM phones) is (800-1900 MHz). If we look at the table of the electromagnetic spectrum, we can see that this range is contained within the frequencies of the microwaves, which include waves in the range 300 MHz-300 GHz.
So, summarizing, the correct answer is "microwaves".
Answer:
Air
Explanation:
The mixing of cooler air in the lower troposphere with air flowing in a different direction in the middle troposphere causes the rotation on a horizontal axis, which, when deflected and tightened vertically by convective updrafts, forms a vertical rotation that can cause condensation to form a funnel cloud.
Answer: Ecosystem
Explained: There's a minimum word count I'm filling up, don't mind me.