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Zolol [24]
3 years ago
7

A ball is thrown upward in the air, and its height above the ground after t seconds is H ( t ) = 63 t − 16 t 2 feet. Find the ti

me t when the ball will be traveling upward at 15.75 feet per second.
Physics
1 answer:
AnnyKZ [126]3 years ago
7 0

Answer:

1.477seconds

Explanation:

The height of the stone thrown in air after t secs is expressed by the equation;

H(t) = (63t − 16t²) feet

Velocity is the change in displacement of the body with respect to time.

V(t) = d(H(t))/dt

V(t) = 63 - 32t

To get the time t when the ball will be traveling upward at 15.75 feet per second, we will substitute V(t) = 15.75 into the resulting equation as shown;

15.75 = 63 - 32t

-32t = 15.75-63

-32t = -47.25

t = 47.25/32

t = 1.477seconds

Hence the ball will be travelling upward when t is 1.477s

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Answer:

2.87 km/s

Explanation:

radius of planet, R = 1.74 x 10^6 m

Mass of planet, M = 7.35 x 10^22 kg

height, h = 2.55 x 10^6 m

G = 6.67 x 106-11 Nm^2/kg^2

Use teh formula for acceleration due to gravity

g=\frac{GM}{R^{2}}

g=\frac{6.67\times 10^{-11}\times 7.35\times 10^{22}}{1.74^{2}\times 10^{12}}

g = 1.62 m/s^2

initial velocity, u = ?, h = 2.55 x 10^6 m , final velocity, v = 0

Use third equation of motion

v^{2}=u^{2}-2gh

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v² = 8262000

v = 2874.37 m/s

v = 2.87 km/s

Thus, the initial speed should be 2.87 km/s.

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The universe could be considered an isolated system because
Stolb23 [73]

Answer:

A(many people think that no energy or matter exists outside the universe)

Explanation:

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This is the upthrust on an object which is placed inside a fluid

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tino4ka555 [31]

Answer:

<h3>25km/hr</h3>

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