Answer:
Since v = (x(2) - x(1)) / t
point 2 obviously has the greatest displacement in a given time
Also, point 2 is the steepest line on this graph.
Idkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidkidk
Answer:
The magnitude of the tension on the ends of the clothesline is 41.85 N.
Explanation:
Given that,
Poles = 2
Distance = 16 m
Mass = 3 kg
Sags distance = 3 m
We need to calculate the angle made with vertical by mass
Using formula of angle



We need to calculate the magnitude of the tension on the ends of the clothesline
Using formula of tension

Put the value into the formula


Hence, The magnitude of the tension on the ends of the clothesline is 41.85 N.
I am going to need a picture for this question
First calculate the <em>percentage of one hr</em> it takes. You can do this by dividing the distance by the velocity. The general formula for this is:

always remember to make sure your units are the same.
so that's 1km by the 950km/h velocity.
1/950 = 0.0010526 hrs
Then multiply that answer by 3600 (<em>the number of seconds in 1 hr</em>) to find how many seconds this is.
0.0010526 * 3600 = 3.789 seconds