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baherus [9]
3 years ago
7

It takes 26.5 N to just pull a 72 kg sled across snow. What is the coefficient of friction?

Physics
1 answer:
Shtirlitz [24]3 years ago
3 0
Assuming g = 10, the weight of the sled is 720N.

If it takes 26.5N to just pull the sled, then the frictional force f is 26.5N in the opposite direction.

f = μ*720N
26.5N = μ*720N
μ = 26.5N/720N = 0.037 (2 s.f.)

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