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Leno4ka [110]
3 years ago
13

The entropy of an isolated system must be conserved, so it never changes.a. Trueb. Fasle

Physics
1 answer:
Snowcat [4.5K]3 years ago
6 0

Answer:

B: False

Explanation:

The second law of thermodynamics states that: the entropy of an isolated system will never decrease because isolated systems always tend to evolve towards thermodynamic equilibrium which is a state with maximum entropy.

Thus, it means that the entropy change will always be positive.

Therefore, the given statement in the question is false.

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A 9-μC positive point charge is located at the origin and a 6 μC positive point charge is located at x = 0.00 m, y = 1.0 m. Find
sukhopar [10]

Answer:

The coordinates of the point is (0,0.55).

Explanation:

Given that,

First charge q_{1}=9\times10^{-6}\ C at origin

Second charge q_{2}=6\times10^{-6}\ C

Second charge at point P = (0,1)

We assume that,

The net electric field between the charges is zero at mid point.

Using formula of electric field

E=\dfrac{kq}{r^2}

0=\dfrac{k\times9\times10^{-6}}{d^2}+\dfrac{k\times6\times10^{-6}}{(1-d)^2}

\dfrac{(1-d)}{d}=\sqrt{\dfrac{6}{9}}

\dfrac{1}{d}=\dfrac{\sqrt{6}}{3}+1

\dfrac{1}{d}=1.82

d=\dfrac{1}{1.82}

d=0.55\ m

Hence, The coordinates of the point is (0,0.55).

3 0
3 years ago
An animal cell placed in pure distilled 100% will
jasenka [17]

in a hypotonic solution like distilled water, a red blood cell would burst, because inside the cell has a higher solute concentration than outside.

In a hypertonic solution, there is a higher solute concentration on the outside of the cell than on the inside, causing the cell to shrivel.

i hope this helps

8 0
3 years ago
A water-skier is being pulled by a tow rope attached to a boat. As the driver pushes the throttle forward, the skier accelerates
Novosadov [1.4K]

Answer:

4334.4 J

Explanation:

Work done equals to kinetic energy change

KE=½mv²

Change in KE is given by

∆KE=½m(v²-u²)

Where m is mass of water-skier, KE is kinetic energy, ∆KE is the change in kinetic energy, v is final velocity and u is initial velocity.

Substituting 72 kg for m, 12.1 m/s for v and 5.10 m/s for u then

∆KE=½*72(12.1²-5.10²)=4334.4J

Therefore, the work done by the net external force acting on the skier is equal to 4334.4 J

6 0
3 years ago
HELP PLZ! A parachutist jumps out of an aeroplane and accelerates uniformly at 9.8 ms-2 for ten seconds. a. How far does she tra
Mrac [35]

Answer:

a.) 490m

b.) 98m/s

Explanation:

Given that the

Acceleration g = 9.8 m/s^2

Time = 10s

Since the parachutist jumps out of an aeroplane. The parachutist jumped out from rest. Initial velocity U is therefore equal to zero. That is,

U = 0

Distance covered = height H

The height can be calculated by using second equation of motion

H = Ut + 1/2gt^2

Substitute g and t into the formula

H = 1/2 × 9.8 × 10^2

H = 490 m

Therefore, she travels as far as 490 m

b.) Her final velocity can be calculated by using third equation of motion

V^2 = U^2 + 2gH

Substitute g and H into the formula.

Remember that U = 0

V^2 = 2 × 9.8 × 490

V^2 = 9604

V = sqrt (9604)

V = 98 m/s

Therefore, her final velocity is 98 m/s

4 0
3 years ago
A wildlife researcher is tracking a flock of geese. the geese fly 3.5 km due west, then turn toward the north by 40 ∘ and fly an
kaheart [24]

To solve this problem, we can use the cosine formula for calculating the length of the displacement:

c^2 = a^2 + b^2 – 2 a b cos θ

 

where c is the displacement, a = 3.5 km, b = 4.5 km, and θ is the angle inside the triangle

 

Since the geeze turned 40° from west to north, so the angle inside the triangle must be:

θ = 180 – 40 = 140°

 

c^2 = 3.5^2 + 4.5^2 – 2 (3.5) (4.5) cos 140

c^2 = 56.63

c = 7.53 km

 

<span>So the magnitude of the displacement is 7.53 km</span>

4 0
3 years ago
Read 2 more answers
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