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Leno4ka [110]
3 years ago
13

The entropy of an isolated system must be conserved, so it never changes.a. Trueb. Fasle

Physics
1 answer:
Snowcat [4.5K]3 years ago
6 0

Answer:

B: False

Explanation:

The second law of thermodynamics states that: the entropy of an isolated system will never decrease because isolated systems always tend to evolve towards thermodynamic equilibrium which is a state with maximum entropy.

Thus, it means that the entropy change will always be positive.

Therefore, the given statement in the question is false.

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Using a simple machine, a student is able to lift a 500N weight by applying only 100N.
NISA [10]
The mechanical advantage of a machine is the ratio between the output force and the input force:
MA= \frac{F_O}{F_I}
In our problem, the input force is 100 N, while the output force is the weight of the object the student lifts, 500 N. So, the mechanical advantage is
MA= \frac{500 N}{100 N}=5
7 0
4 years ago
Estimate the Joule-Thomson coefficient of refrigerant-134a at 0.70 MPa and 50°C. Assume the second state will be selected for a
leva [86]

Answer:

\mu = 0.018\,\frac{^{\textdegree}C}{kPa}

Explanation:

The Joule-Thomson coefficient is the ratio of the change of temperature to the change of pressure under isoenthalpic conditions:

\mu = \left(\frac{\Delta T}{\Delta P}\right)_{h}

Initial and final properties are:

T_{1} = 50^{\textdegree}C, P_{1}=700\,kPa, h_{1}=288.54\,\frac{kJ}{kg}. Superheated Vapor.

T_{2} = 48.186^{\textdegree}C, P_{2}=600\,kPa, h_{2}=288.54\,\frac{kJ}{kg}. Superheated Vapor.

The Joule-Thomson coefficient is approximately:

\mu = \frac{50^{\textdegree}C-48.186^{\textdegree}C}{700\,kPa-600\,kPa}

\mu = 0.018\,\frac{^{\textdegree}C}{kPa}

5 0
4 years ago
What times what equals 400
Radda [10]

If you're willing to consider fractions or decimals,
then there are an infinite number of answers. 
Like (2.5 x 160), and (15 x 26-2/3).

If you want to stick to only whole numbers,
then these 8 combinations do:

1, 400
2, 200
4, 100
5, 80
8, 50
10, 40
16, 25
20, 20

7 0
4 years ago
Which element listed would have the greatest electronegativity?
DiKsa [7]

Answer:

A. Fluorine

Explanation:

This is because it has the smallest atomic radius.

{ \tt{}}

7 0
3 years ago
Read 2 more answers
A spherical wave with a wavelength of 2.0 mm is emitted from the origin. At one instant of time, the phase at rrr = 4.0 mm is πr
max2010maxim [7]

Complete Question

A spherical wave with a wavelength of 2.0 mm is emitted from the origin. At one instant of time, the phase at r_1 = 4.0 mm is π rad. At that instant, what is the phase at r_2 = 3.5 mm ? Express your answer to two significant figures and include the appropriate units.

Answer:

The phase at the second point is  \phi _2  = 1.57 \  rad

Explanation:

From the question we are told that

    The wavelength of the spherical wave is  \lambda =  2.0 \ mm =  \frac{2}{1000} = 0.002 \ m

    The first radius  is  r_1  = 4.0 \ mm  = \frac{4}{1000}  = 0.004 \ m

     The phase at that instant is  \phi _1 = \pi \ rad

     The second radius is  r_2  = 3.5 \ mm  = \frac{3.5}{1000}  = 0.0035 \ m

Generally the phase difference is mathematically represented as

          \Delta  \phi =  \phi _2 -  \phi _1

this can also be expressed as

         \Delta \phi =  \frac{2 \pi }{\lambda } (r_2 - r_1 )

So we have that

   \phi _2 -  \phi _1 =   \frac{2 \pi }{\lambda } (r_2 - r_1 )

substituting values

     \phi _2 -  \pi =   \frac{2 \pi }{0.002 } ( 0.0035 - 0.004 )

    \phi _2  =   \frac{2 \pi }{0.002 } ( 0.0035 - 0.004 ) +   3.142

   \phi _2  = 1.57 \  rad

7 0
3 years ago
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