what is the result of 6.2×10 to the fourth power times 3.3×10 to the second power express in scientific notation

On a part time job you are asked to bring a cylindrical iron rod of density 7800 kg/m^3, length 81.2 cm and diameter 2.75 cm fro

Hitman42 [59]

Answer:

3.76188 kg

36.9040428 N

Yes

Explanation:

g = Acceleration due to gravity = 9.81 m/s²

L = Length of rod = 81.2 cm

d = Diameter of rod = 2.75 cm

r = Radius = $\frac{d}{2}=\frac{2.75}{2}=1.375\ cm$

A = Area of the cylinder = $\pi r^2$

v = Volume = $L\times A$

m = Mass

$\rho$ = Density of rod = 7800 kg/m³

Density

$\rho=\dfrac{m}{v}\\\Rightarrow m=\rho\times v\\\Rightarrow m=\rho\times L\times A\\\Rightarrow m=7800\times 0.812\times \pi\times 0.01375^2\\\Rightarrow m=3.76188\ kg$

The mass of the rod is 3.76188 kg.

As the the mass of the rod is 3.76188 kg I will be able to carry the rod.

Weight

$W=mg\\\Rightarrow W=3.76188\times 9.81\\\Rightarrow W=36.9040428\ N$

The weight of the rod is 36.9040428 N

7 0

3 years ago

I’ll give brainliest

stellarik [79]

<h2>Hey there! </h2>

<h2>The correct option is:</h2>

<h3>"Government" </h3>

<h2>Explanation:</h2>

<h3>Government is responsible for ruling an authority in a proper way, so the answer is Government. </h3>

8 0

2 years ago

The space shuttle releases a satellite into a circular orbit 630 km above the Earth.

solniwko [45]

Answer:

7,539 m/s

Explanation:

Let's use this equation to find the gravitational acceleration of this space shuttle:

$\displaystyle g=\frac{GM}{r^2}$

We know that G is the gravitational constant: 6.67 * 10^(-11) Nm²/kg².

M is the mass of the planet, which is Earth in this case: 5.972 * 10^24 kg.

r is the distance from the center of Earth to the space shuttle: radius of Earth (6.3781 * 10^6 m) + distance above the Earth (630 km → 630,000 m).

Plug these values into the equation:

$\displaystyle g=\frac{(6.67\cdot 10^-^1^1 \ Nm^2kg^-^2)(5.972\cdot 10^2^4 \ kg)}{[(6.3781\cdot 10^6 \ m)+(630000 \ m)]^2}$

Remove units to make the equation easier to read.

$\displaystyle g=\frac{(6.67\cdot 10^-^1^1 )(5.972\cdot 10^2^4 )}{[(6.3781\cdot 10^6)+(630000 )]^2}$

Multiply the numerator out.

$\displaystyle g=\frac{(3.983324\cdot 10^1^4)}{[(6.3781\cdot 10^6)+(630000 )]^2}$

Add the terms in the denominator.

$\displaystyle g=\frac{(3.983324\cdot 10^1^4)}{[(7008100)]^2}$

Simplify this equation.

$\displaystyle g=8.11045189 \ \frac{m}{s^2}$

The acceleration due to gravity g = 8.11045189 m/s². Now we use the equation for acceleration for an object in circular motion which contains v and r.

$\displaystyle a = \frac{v^2}{r}$

a = g, v is the velocity that the space shuttle should be moving (what we are trying to solve for), and r is the radius we had in the previous equation when solving for g.

Plug these values into the equation and solve for v.

$\displaystyle 8.11045189 \ \frac{m}{s^2} = \frac{v^2}{7008100 \ m}$

Remove units to make the equation easier to read.

$\displaystyle 8.11045189 = \frac{v^2}{7008100}$

Multiply both sides by 7,008,100.

$56838857.89=v^2$

Take the square root of both sides.

$v=7539.154985$

The shuttle should be moving at a velocity of about 7,539 m/s when it is released into the circular orbit above Earth.

5 0

3 years ago

What is ohms law <br><br><br>PLEASE ANSWER THIS I NEED IT FAST

Lorico [155]

Answer:

Ohms law states that current is directly proportional to the potential difference across the ends of a conductor provided that temperature and other factors kept constant

$V=I(R)$

6 0

3 years ago

A scientist travelled 80 kilometres each day in the buggy.

7nadin3 [17]

Explanation:

In one day a scientist can travel = 80 km

In 10 days. a scientist can travel = 80* 10

= 800 km.

4 0

3 years ago

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