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ikadub [295]
3 years ago
15

On a part time job you are asked to bring a cylindrical iron rod of density 7800 kg/m^3, length 81.2 cm and diameter 2.75 cm fro

m a storage room to a machinist. Calculate the weight of the rod, w. The acceleration due to gravity, g= 9.81 m/s^2.
w= 36.9 N Part A

Part B) Now that you know the weight of the rod, do you think that you will be able to carry the rod without a cart? Yes or No?
Physics
1 answer:
Hitman42 [59]3 years ago
7 0

Answer:

3.76188 kg

36.9040428 N

Yes

Explanation:

g = Acceleration due to gravity = 9.81 m/s²

L = Length of rod = 81.2 cm

d = Diameter of rod = 2.75 cm

r = Radius = \frac{d}{2}=\frac{2.75}{2}=1.375\ cm

A = Area of the cylinder =\pi r^2

v = Volume = L\times A

m = Mass

\rho = Density of rod = 7800 kg/m³

Density

\rho=\dfrac{m}{v}\\\Rightarrow m=\rho\times v\\\Rightarrow m=\rho\times L\times A\\\Rightarrow m=7800\times 0.812\times \pi\times 0.01375^2\\\Rightarrow m=3.76188\ kg

The mass of the rod is 3.76188 kg.

As the the mass of the rod is 3.76188 kg I will be able to carry the rod.

Weight

W=mg\\\Rightarrow W=3.76188\times 9.81\\\Rightarrow W=36.9040428\ N

The weight of the rod is 36.9040428 N

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