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gtnhenbr [62]
3 years ago
14

Silvia is driving at the speed limit of 25 m/s when she sees an ambulance approaching in her rear view mirror to the move out of

its way , she accelerated to 32 m/s in 3 s . How far did she travel during those 3 s
Physics
1 answer:
notka56 [123]3 years ago
6 0

KINEMATICS

Uniform or constant motion in a straight line (rectilinear). Speed or velocity constant and/or acceleration constant. If motion is up and down and/or has an up and down component then acceleration omn earth will be g. g is about 10m/s/s.


speed = distance/time

velocity = displacement/time

s=distance ... u=initial speed ... v = final speed ... a = acceleration ... t = time


v=u+at

v^2=u^2+2as

s=ut+1/2at^2

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A series RCL circuit consists of a 50 Ω resistor, 500 Ω capacitor, and a 500 Ω inductor. What is the angle of impedance?
lbvjy [14]

Answer:

Zero

Explanation:

here, the inductive reactance and the capacitive reactance is same, so this is the condition for resonance.

In the condition for resonance,

the circuit and the voltage in the circuit is in the same phase and the impedance of the circuit is minimum which is equal to the resistance of the circuit.

The phase angle is given by

tan\phi =\frac{X_{L}-X_{C}}{R}

Ф = 0

5 0
3 years ago
A measure of the quantity of matter is<br> a. density.<br> c. force.<br> b. weight.<br> d. mass.
ohaa [14]
A measure of the quantity of matter is called mass. D.

This is how much of matter is contained in an object. It is different from weight, which is the pull of gravity on an object.  
6 0
3 years ago
An electron (charge = –1.6 x 10–19 C) is moving at 3.0 x 105 m/s in the positive x direction. A magnetic field of 0.80 T is in t
Marta_Voda [28]

Answer:

F = 3.84*10^-34N ^j

Explanation:

In order to calculate the magnetic force on the electron you use the following formula:

\vec{F}=q\vec{v} \ X\ \vec{B}       (1)

q: charge of the electron = -1.6*10^-19C

B: magnitude of the magnetic field = 0.80T

v: speed of the charge = 3.0*10^5 m/s

The direction of the motion of the electron is in the +i^ direction (+x direction). The magnetic field is in the +^k direction (+z direction).

The cross product between these unit vectors, by taking into account the minus sign of the charge, is given by:

-^i X ^k = ^j

The magnetic force is in the ^j direction (+y direction).

The magnitude of the magnetic force is:

F=qvB=(1.6*10^{-19}C)(3.0*10^5m/s)(0.80T)=3.84*10^{-34}N

The magnetic force on the electron has a magnitude of 3.84*10^-34N in the +y direction

7 0
3 years ago
A race car starting from rest accelerates uniformly at a rate of 3.90 m/s^2 what is the cars speed after it has traveled 200 m.
snow_tiger [21]
The formula for accelerational displacement is at^2/2, so we know that 3.9t^2/2 = 200, or 3.9t^2 = 400. t = \sqrt{400/3.9} \approx 10.12739367, at = v, so 3.9 * 10.12739367 \approx 39.5  m/s
6 0
3 years ago
Read 2 more answers
1. A 3.5 kg object experiences an acceleration of 0.5 m/s2. What net force does the object experience
Leviafan [203]

Answer:

<h2>1.75 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 3.5 × 0.5 = 1.75

We have the final answer as

<h3>1.75 N</h3>

Hope this helps you

7 0
3 years ago
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