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scoray [572]
2 years ago
9

SORRY LAST ONE FOR TODAY, IM GOING TO PASS IF I GET THIS ANSWERED

Physics
2 answers:
faust18 [17]2 years ago
6 0

Answer:

<u>According </u><u>to</u><u> the</u><u> </u><u>Given</u><u> Statement</u><u> </u>

Canon fires directly upwarda at 150m/s ( Initial speed, u )

Acceleration due to gravity is 10m/s²

Since Cannon ball reach it maximum height so its final velocity v will be 0 m/s .

Using Kinematic Equation

  • v = u + gt

On substituting the value we get

➥ 0 = 150 + 10 × t

➥ 150 = 10 × t

➥ 150/10 = t

➥ 15 s = t

So, it will take 15 seconds .

vladimir1956 [14]2 years ago
3 0

Answer:

maximum height reached: 15 s

Explanation:

using the formula: maximum height reached = [(sin(θ) * speed)/ gravity]

Here speed is 150m/s and gravity is 10 m/s² and as it does directly upwards, it has an angle of 90°

using the formula:

maximum height reached = [(sin(90) * 150)/ 10] = 15 s

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A child walks due east on the deck of a ship at 2 miles per hour. the ship is moving north at a speed of 18 miles per hour. find
garik1379 [7]
Refer to the figure shown below.

The velocity of the child and the velocity of the ship should be added vectorially to find the speed and direction of the child relative to the water surface.

The magnitude of the child's velocity is
v = √(2² + 18²) = 18.11 mph

The direction of the child's speed is
θ = tan⁻¹ (18/2) = tan⁻¹ 9 = 83.7° north of east or counterclockwise from the eastern direction.

Answer:
The magnitude is 18.1 mph.
The direction is 84° north of east.

8 0
3 years ago
When a object slows down what direction is the force going?
trapecia [35]

Answer: when a object gets slowed down, it's force is either going into friction and drag, if it's on the ground, and weight+drag+friction, if it's in the air.

Explanation:

7 0
3 years ago
A train whistle is heard at 300 Hz as the train approaches town. The train cuts its speed in half as it nears the station, and t
spin [16.1K]

Answer:

The speed of the train before and after slowing down is 22.12 m/s and 11.06 m/s, respectively.

Explanation:

We can calculate the speed of the train using the Doppler equation:

f = f_{0}\frac{v + v_{o}}{v - v_{s}}        

Where:

f₀: is the emitted frequency

f: is the frequency heard by the observer  

v: is the speed of the sound = 343 m/s

v_{o}: is the speed of the observer = 0 (it is heard in the town)

v_{s}: is the speed of the source =?

The frequency of the train before slowing down is given by:

f_{b} = f_{0}\frac{v}{v - v_{s_{b}}}  (1)                  

Now, the frequency of the train after slowing down is:

f_{a} = f_{0}\frac{v}{v - v_{s_{a}}}   (2)  

Dividing equation (1) by (2) we have:

\frac{f_{b}}{f_{a}} = \frac{f_{0}\frac{v}{v - v_{s_{b}}}}{f_{0}\frac{v}{v - v_{s_{a}}}}

\frac{f_{b}}{f_{a}} = \frac{v - v_{s_{a}}}{v - v_{s_{b}}}   (3)  

Also, we know that the speed of the train when it is slowing down is half the initial speed so:

v_{s_{b}} = 2v_{s_{a}}     (4)

Now, by entering equation (4) into (3) we have:

\frac{f_{b}}{f_{a}} = \frac{v - v_{s_{a}}}{v - 2v_{s_{a}}}  

\frac{300 Hz}{290 Hz} = \frac{343 m/s - v_{s_{a}}}{343 m/s - 2v_{s_{a}}}

By solving the above equation for v_{s_{a}} we can find the speed of the train after slowing down:

v_{s_{a}} = 11.06 m/s

Finally, the speed of the train before slowing down is:

v_{s_{b}} = 11.06 m/s*2 = 22.12 m/s

Therefore, the speed of the train before and after slowing down is 22.12 m/s and 11.06 m/s, respectively.                        

I hope it helps you!                                                        

7 0
2 years ago
PLEASE HELP COME UP WITH 5 MULTIPLE CHOICE QUESTIONS FROM HEALTH RELATED FITNESS AND SKILL RELATED QUESTIONS
Helga [31]

Answer:

1. What is not considered a cardiovascular workout?

A. Jogging

B. Sit ups

C. Jump Ropes

D. Burpees

Explanation:

I am sorry, I am in middle school and I only have one question.

5 0
2 years ago
How is item A different from Item B?
iris [78.8K]

Explanation:

well there is nothing there and it could be different by diffrent objects, idk

8 0
3 years ago
Read 2 more answers
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