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zepelin [54]
3 years ago
9

Kinetic energy is the energy an object has due to its

Physics
2 answers:
lara31 [8.8K]3 years ago
6 0

Answer:

potential energy or stored energy

Explanation:

sveticcg [70]3 years ago
5 0

Answer:

Motion

Explanation:

Edge2021

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What is the largest planet in our galaxy
ludmilkaskok [199]
In our Solar System, Jupiter is the largest planet we have. it has the surface area of 23.71 billion mi^2. it beats all the other planets in both mass and volume.
4 0
3 years ago
How long does it take for an airplane to change its velocity from 140 m/s to 180 m/s if its
kobusy [5.1K]

Answer:

Explanation:

a = 4ms⁻²,  Vf = 180 m/s  &  Vi = 140m/s

a = \frac{Vf-Vi}{t}

4 = \frac{180-140}{t}

t = 40/4

t = 10sec

To Measure Distance Use third Equation of Motion:

2aS = Vf²-Vi²

S = \frac{180*180 - 140*140}{2(4)}

S = 12800/8 = 1600m

4 0
3 years ago
Green light (λ = 518 nm) strikes a single slit at normal incidence. What width slit will produce a central maximum that is 3.00
MariettaO [177]

Answer:

6.9066 × 10⁻⁵ m

Explanation:

For constructive interference, the expression is:

d\times sin\theta=m\times \lambda

Where, m = 1, 2, .....

d is the distance between the slits.

The formula can be written as:

sin\theta=\frac {\lambda}{d}\times m ....1

The location of the bright fringe is determined by :

y=L\times tan\theta

Where, L is the distance between the slit and the screen.

For small angle , sin\theta=tan\theta

So,  

Formula becomes:

y=L\times sin\theta

Using 1, we get:

y=L\times \frac {\lambda}{d}\times m

Thus, the distance between the central maximum is 3.00 cm

First bright fringe , m = 1 occur at 3.00 / 2 = 1.50 cm

Since,

1 cm = 0.01 m

y = 0.0150 m

Given L = 2.00 m

λ = 518 nm

Since, 1 nm = 10⁻⁹ m

So,

λ = 518 × 10⁻⁹ m

Applying the formula as:

0.0150\ m=2.00\ m\times \frac {518\times 10^{-9}\ m}{d}\times 1

<u>⇒ d, distance between the slits = 6.9066 × 10⁻⁵ m</u>

7 0
3 years ago
how much gravitational potential energy does a 5 kg rock have if is sitting on the edge of a cliff that is 10m high
docker41 [41]
Gpe =5 x 9.8 x 10 = .... Joules
8 0
3 years ago
Sherlock Holmes is using an 9.99-cm-focal-length lens as his magnifying glass. To obtain maximum magnification, where must the o
Karolina [17]

Answer:

The object must be placed just ahead of focus towards the lens.

Explanation:

As we know that a magnifying glass is a convex lens and for the convex lens and for a convex lens we get the image virtual, erect and magnified only when it is placed between the optical center and the focus of the lens.

In that range when the object is nearest to the focus of the lens it has the maximum size.

So it can be possible if the object is placed at 9.98 cm from the optical center.

The largest image is formed at infinity when the object is placed at focus but it is not visible to the normal eyes.

5 0
3 years ago
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