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DedPeter [7]
3 years ago
15

Emily sprains her ankle on her way home from school. Her mom suggests she use an “instant cold pack” to reduce the swelling. Whe

n Emily’s mom hands her the cold pack, it is room temperature. The instructions on the pack tell Emily to pop a button inside the ice pack to open a packet of chemicals. Once Emily has popped the button, she notices that the cold pack immediately gets cold. She places it on her swollen ankle. Write a thoughtful and complete response (3+ sentences) that describes what happened to the energy as it is first in the cold pack (before Emily pops the button), then when she pushes the button, and then after Emily has placed the cold pack on her ankle. Discuss transfers and transformations of the energy.
Physics
1 answer:
tresset_1 [31]3 years ago
4 0
<span>In energy transfer, happens from one object to another without changing its form. For example, when you fill a pot of water and sit it on the stove, the water continues to heat until you turn it off. While in a energy transformation, the energy changes forms such as Chemical, kinetic.</span>
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Help with physics projectile motion​
BlackZzzverrR [31]

Answer:

10.4 m/s

Explanation:

First, find the time it takes for the projectile to fall 6 m.

Given:

y₀ = 6 m

y = 0 m

v₀ = 0 m/s

a = -9.8 m/s²

Find: t

y = y₀ + v₀ t + ½ at²

(0 m) = (6 m) + (0 m/s) t + ½ (-9.8 m/s²) t²

t = 1.11 s

Now find the horizontal position of the target after that time:

Given:

x₀ = 6 m

v₀ = 5 m/s

a = 0 m/s²

t = 1.11 s

Find: x

x = x₀ + v₀ t + ½ at²

x = (6 m) + (5 m/s) (1.11 s) + ½ (0 m/s²) (1.11 s)²

x = 11.5 m

Finally, find the launch velocity needed to travel that distance in that time.

Given:

x₀ = 0 m

x = 11.5 m

t = 1.11 s

a = 0 m/s²

Find: v₀

(11.5 m) = (0 m) + v₀ (1.11 s) + ½ (0 m/s²) (1.11 s)²

v₀ = 10.4 m/s

3 0
3 years ago
Một chất điểm DĐĐH có phương trình x=Acos(omega t). Tìm thời gian chất điểm qua vtcb theo chiều dương lần thứ 2?
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Answer:

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8 0
3 years ago
A uniform rod is set up so that it can rotate about a perpendicular axis at one of its ends. The length and mass of the rod are
igor_vitrenko [27]

Answer:

0.231 N

Explanation:

To get from rest to angular speed of 6.37 rad/s within 9.87s, the angular acceleration of the rod must be

\alpha = \frac{\theta}{t} = \frac{6.37}{9.87} = 0.6454 rad/s^2

If the rod is rotating about a perpendicular axis at one of its end, then it's momentum inertia must be:

I = \frac{mL^2}{3} = \frac{1.27*0.847^2}{3} = 0.303kgm^2

According to Newton 2nd law, the torque required to exert on this rod to achieve such angular acceleration is

T = I\alpha = 0.303*0.6454 = 0.196 Nm

So the force acting on the other end to generate this torque mush be:

F = \frac{T}{L} = \frac{0.196}{0.847} = 0.231 N

4 0
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r-ruslan [8.4K]

Answer:

D.

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the friction forces are smaller than the forward force

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