Question

What is the force, in units of femtoNewtons, on an electron moving at a velocity of 7.26 x 106 ms-1 perpendicularly to a magnetic field when the magnetic flux density of 0.049 T?

Answer 1

Answer:

56.9 fN

Explanation:

The force exerted on the electron is:

$F=Bqv$

where

B is the magnetic field strength

q is the electron's charged

v is the speed of the electron

In our problem,

B = 0.049 T

$q=1.6\cdot 10^{-19} C$

$v=7.26\cdot 10^6 m/s$

Therefore, the force is

$F=(0.049 T)(1.6\cdot 10^{-19} C)(7.26\cdot 10^6 m/s)=5.69\cdot 10^{-14} N=56.9 fN$