Answer:

Explanation:
As we know that the angle of incidence is given as

also we have angle of refraction as

now by Snell's law we know that


now we have


From the calculations, the final momentum of B is 8.16 m/s
<h3>What is conservation of linear momentum?</h3>
According to the principle of the conservation of linear momentum, the momentum before collision is equal to the total momentum after collision.
This implies that;
MaUa + MbUb = MaVa + MaVa
Substituting values;
(0.08 kg * 0.5 m/s) + (0.05 kg * 0 m/s) = (0.08 kg * −0.1 m/s) + (0.05 kg * v)
0.4 = -0.008 + 0.05v
v = 8.16 m/s
Learn more about more about momentum: brainly.com/question/24030570:
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Explanation:
Given that,
Average power of sun 
We need to calculate the intensity of light at Earth's position
Using formula of intensity

Where, I = intensity
P = power
Put the value into the formula


So, The intensity is 1347.616 W/m².
(A). We need to calculate the pressure on a solar sail due to the light of the sun if it's fully reflective
Using formula for fully reflective

Put the value into the formula


(B). We need to calculate the pressure on a solar sail due to the light of the sun if it's fully reflective
Using formula for fully absorptive



Hence, This is the required solution.
The correct answer of this question is : A) Change alternating current into direct current.
EXPLANATION :
As per the question, we are given vacuum tube. Vacuum tube can be of various types. Normally it contains two electrodes called cathode and anode which are enclosed in an evacuated glass chamber . There are also other types of vacuum tubes which contain extra electrodes like control grid .
The vacuum tube can be used as a rectifier. It means that it can be used as an electronic device which will convert alternating current into direct current. It may be a half wave rectifier or a full wave rectifier. Actually the direct current obtained during the rectification of alternating current is pulsating in nature.
Hence, the correct answer is that a vacuum tube can be used to change alternating current into direct current.
Answer:
The Moon's distance from the Earth varies during its orbit
Explanation:
The correct statement is ,The Moon's distance from the Earth varies during its orbit.
Important point regarding moon:
1 .Moon is a natural satellite of the earth.
2. Moon is the fifth largest satellite in solar system.
3.Second densest satellite in solar system.
4.Moon rotates about earth.
5.Moon is an astronomical body .