Answer:
a ) I= 1.635-i0.0021 b) ∅= -0.074
Explanation:
a) reactive impeadance= 2πfL
=2(3.14)(147)(0.158)
=145.86 Ω
Z= 171+j145.86
I=V/Z
I=278/(171+j145.86)
I= 1.635-i0.0021
b) ∅=inv.tan (-0.0021/1.635)
∅=-0.074
Part 1- The work done by the gas during this process will be 5.65 ×10⁻³ kJ.
Part 2-The heat added to the gas during this process will be 5.65 ×10×10⁻³ kJ.
<h3>What is work done by the gas?</h3>
Work is the product of pressure p and volumes V during a volume change for such a gas. The work seems to be the area under the curve that indicates how the state changes.
The work done under the isothermal process is;

For the isothermal process;
ΔU=0

Hence, the work done, and the heat added by the gas during this process will be 5.65 ×10⁻³ kJ and 5.65 ×10×10⁻³ kJ respectively.
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Answer:
They have three to six valence electrons, so they can lose or gain electrons.
Explanation:
I just took the quiz on Edgenuity.
Work done by force is given by formula

now here work done against friction is given so force of friction here is

It moved by three corridors with each measures

so total distance will be

now from above formula of work done we will say


so above is the work done to move three corridors