The car has gravitational potential energy (Eg)
Eg = mgh
Eg = (53kg) (9.81N/kg) (14m)
Eg = 7 279.02 J
Answer:
(i) Electric field outside the shell:
For point r>R; draw a spherical gaussian surface of radius r.
Using gauss law, ∮E.ds=q0qend
Since E is perpendicular to gaussian surface, angle betwee E is 0.
Also E being constant, can be taken out of integral.
So, E(4πr2)=q0q
So, E=4πε01r2q
Given :
A jogger runs 5.0 km on a straight trail at an angle of 60° south of west.
To Find :
The southern component of the run rounded to the nearest tenth of a kilometre.
Solution :
We know, southern component is given by :

Here, negative sign indicates south direction.
Therefore, the southern component of the run rounded to the nearest tenth of a kilometre is 4.3 km.
Hence, this is the required solution.
A. The position of stars move throughout the year due to gravity