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faltersainse [42]
3 years ago
7

The first ionization energies (kl/mol) of hydrogen (H), nitrogen (N), fluroine (F), and oxygen (O) are 1,312, 1,402, 1,742, and

1,314, respectively. From which electrically neutral atom does it take the least energy to remove the first electron?
• Hydrogen
• Fluorine
• Nitrogen
• Oxygen
Chemistry
1 answer:
Oksanka [162]3 years ago
5 0
Fluorine because of the spin pair repulsion fron the p orbitals
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F^{-} is most abundant and 6310 times more than HF.

<h3>What is a strong and weak acid?</h3>

When an acid is dissolved in water, all of its molecules disintegrate, making the acid powerful.

When an acid is dissolved in water, only a small number of its molecules disintegrate, making the acid weak. Strong acids have a lower pH than weak acids.

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Given:

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pH=pka+log \frac{F^{-}}{HF} \\\\7=3.2+log\frac{F^{-}}{HF} \\3.8=log\frac{F^{-}}{HF}\\ \frac{F^{-}}{0.1}=10^{3.8} \\F^{-}=630.95 M

Now,

\frac{F^{-}}{HF}=\frac{630.95}{0.1}\\ =6309.57

F-:HF= 6309.57:1

Therefore, the most abundant is F^{-}and has 6310 times more than HF is F^{-}.

To know more about strong and weak acids, visit: brainly.com/question/12811944

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