Answer:
19.488 kJ
Explanation:
The overall reaction mechanism shows the reaction between LiCl and H₂O
-------- (1)
-------- (2)
--------- (3)
---------- (4)
The overall reaction =
The heat effects of the above reactions from 1-4 respectively are in the order ; 11311.34 kJ, -857.49 kJ, -873.61 kJ and 439.288kJ respectively
The overall enthalpy change is:
at constant pressure;
Thus; Q = 1311.3 (kJ) 857.49 (kJ) -873.61 (kJ) + 439.288 (kJ)
Q = 19.488 kJ
Thus, the heat effect = 19.488 kJ after the addition of 1 mol of LiCl⋅3H2O(s)
S waves
- The motion of the medium is perpendicular to direction of propagation of the wave
.
- They can propagate only through solids and not through gases or liquids
.
- They travel with less speed
.
P waves
- These are compression waves
.
- These waves produces a force along the direction of propagation
.
- They can propagate through solids, gases and liquids.
- P waves are smaller than s waves
.
- They travel with 60% greater speed than S waves
.
P-waves travel 60% faster than S-waves on average because the interior part of the Earth does not react the same way as the s wave and P wave.
Power source (battery/energy) a copper/metal wire, and then a receiver
Answer:
1s² 2s²2p⁶ 3s²3p⁶ 4s²3d¹⁰4p⁶ 5s²4d¹⁰
Explanation:
Cd is the last element in the 4d block of the Periodic Table (see Figure).
It has the electron configuration of Kr, plus filled 5s and 4d subshells.
Thus, its electron configuration is
1s² 2s²2p⁶ 3s²3p⁶ 4s²3d¹⁰4p⁶ 5s²4d¹⁰
Answer:
10.86
Explanation:
Given that:
Concentration = 0.0288 M
Consider the ICE take for the dissociation of ammonia as:
NH₃ + H₂O ⇄ NH₄⁺ + OH⁻
At t=0 0.0288 - -
At t =equilibrium (0.0288-x) x x
The expression for dissociation constant of ammonia is:
![K_{b}=\frac {\left [ NH_4^{+} \right ]\left [ {OH}^- \right ]}{[NH_3]}](https://tex.z-dn.net/?f=K_%7Bb%7D%3D%5Cfrac%20%7B%5Cleft%20%5B%20NH_4%5E%7B%2B%7D%20%5Cright%20%5D%5Cleft%20%5B%20%7BOH%7D%5E-%20%5Cright%20%5D%7D%7B%5BNH_3%5D%7D)
x is very small, so (0.0288 - x) ≅ 0.0288
Solving for x, we get:
x = 7.2×10⁻⁴ M
pOH = -log[OH⁻] = -log(7.2×10⁻⁴) = 3.14
Also,
pH + pOH = 14
So, pH = 10.86
