HELP ME PLEASE I NEED THE ANDEER NOW

What new characteristic did John Delton add to the model of the atom BRAINLY WHOEVER GETS IT RIGHT PLEASE IM ON A TIMER

madam [21]

Answer: An atom can join with other kinds of atoms.

PLEASE GIVW ME BEAINLY LOLLL

7 0

3 years ago

CH4 and CH3CH2CH3 have the lowest boiling points because they experience only \rm CH_4 and \rm CH_3CH_2CH_3 have the lowest boil

ki77a [65]

Answer:

Dispersion forces

Relative molecular mass

Explanation:

Alkanes experience only dispersion forces. Dispersion forces increase with increasevin the relative molecular mass of the compounds. Hence a higher relative molecular mass implies greater dispersion forces and a greater boiling point.

6 0

2 years ago

what is the molar mass of a gaseous flouride of sulfur containing 70.4% F and having a density of approximately 4.5g/L at 20 deg

zlopas [31]

Answer:

The molar mass is 180.2 g/mol

Explanation:

Step 1: Data given

% of F = 70.4 %

Density = 4.5 g/L

Temperature = 20 °C

Pressure = 1 atm

Step 2: Calculate the number of moles

PV = nRT

⇒ with P = the pressure = 1.00 atm

⇒ with V = the volume = Assume this is 1L

⇒ with n = the number of moles = TO BE DETERMINED

⇒ R = the gas constant = 0.08206 L*atm/K*mol

⇒ T = the temperature : 20°C = 293 Kelvin

1 atm*1L= n(0.08206 L-atm/mol-K)*(293 K)

n = 0.04159 moles

Step 3: Calculate molar mass

Molar mass = Mass / moles

4.5 grams / 0.04159 moles = 108.2 g/mol

Step 4: Calculate moles of F

Moles = Mass / molar mass

Moles F = 70.4 g / 19 g/mol

Moles F = 3.70 moles

Moles S = 29.6g / 32.07 g/mol

Moles S = 0.923 moles S

Step 5: Divide by the smallest amount of moles

F = 3.70 / 0.923 = 4

S = 0.923 / 0.923 = 1

The empirical formula is SF4

The molar mass of SF4 = 32.07 + 4*19 = 108.07 g/mol

This means the empirical formula is the same as the molecular formula SF4

The molar mass is 180.2 g/mol

4 0

2 years ago

Carbon dioxide is one of the main gases in the mixture of gases coming out of the kiln.

Gre4nikov [31]

Because the kiln utilizes fire, fire uses oxygen and the fuel to create CO2
CO2 would be the main gas because the main components of the reactants are carbon and oxygen, which make up CO2

3 0

3 years ago

A balloon contains 5L of oxygen at a pressure of 90 kPa. How much oxygen will the ballon contain if the pressure is lowered to 6

VLD [36.1K]

We have that all (ideal) gases obey the fundamental gas equation: PV=nRT where P is the Pressure, V is the Volume, n is the number of moles, R is a universal constant and T is the temperature in Kelvin. In this process, we have that both the number of moles and the temperature stays the same. So if we denote by i the initial conditions and by f the final conditions of the gas, we have: $P_{i} * V_{i}=nRT= P{f}*V{f}$ . Hence, if we solve for the final Volume we get: $V_{f} = \frac {V_{i}*P_{i} }{P_{f}}$ . Now we know all the other variables; substituting we get that the final volume is 6.7 L (6.716 L ).

3 0

3 years ago

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