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Gala2k [10]
3 years ago
14

Suspect A is actually telling the truth and they describe the events of a certain evening with confidence. After being asked to

do so, suspect A then retells the events of the same evening in the reverse order. What is this suspect relying on?
The inexperience of the interrogator


The ability to confuse the interrogator


The power of their memory


The power of their ability to lie
Chemistry
1 answer:
lorasvet [3.4K]3 years ago
7 0

It seems like the answer is C, you really just need to use the process of elimination.

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Given 65 g of C3 H8 and 65 g of O2, what is the theoretical yield of CO2 in grams
Helga [31]

Answer:

Yeild of CO2 is approximately 54g

Explanation:

Using reaction stoichiomety and coeeficients, and knowing O2 is limiting reactant, 54 g of CO2 is produced.

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This is Q7 and I need help, can someone help.
andre [41]

Answer:

Answer to A. helium, neon, argon, krypton, xenon, and radon, B. Elemental hydrogen (H, element 1), nitrogen (N, element 7), oxygen (O, element 8), fluorine (F, element 9), and chlorine (Cl, element 17) are all gases at room temperature, and are found as diatomic molecules (H2, N2, O2, F2, Cl2). C. Elements Compounds

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5 0
3 years ago
Suppose a thermometer has marks at every one degree increment and the mercury level on the thermometer is exactly between the 25
alekssr [168]

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5 0
3 years ago
The table describes how some substances were formed.
lisabon 2012 [21]

Explanation:

Which is a pure substance?

1. soda

2. gasoline

3. salt water

4. carbon dioxide

carbon dioxide

Bromine, a liquid at room temperature, has a boiling point of 58°C and a melting point of -7.2°C. Bromine can be classified as a

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6 0
3 years ago
Read 2 more answers
The pressure in a car tire is 198 kPa at 27°C. After a long drive, the pressure
AlekseyPX

Answer : The temperature of the air in the tire is, 341 K

Explanation :

Gay-Lussac's Law : It is defined as the pressure of the gas is directly proportional to the temperature of the gas at constant volume and number of moles.

P\propto T

or,

\frac{P_1}{T_1}=\frac{P_2}{T_2}

where,

P_1 = initial pressure = 198 kPa

P_2 = final pressure = 225 kPa

T_1 = initial temperature = 27^oC=273+27=300K

T_2 = final temperature = ?

Now put all the given values in the above equation, we get:

\frac{198kPa}{300K}=\frac{225kPa}{T_2}

T_2=340.9K\approx 341K

Therefore, the temperature of the air in the tire is, 341 K

5 0
3 years ago
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