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Gala2k [10]
3 years ago
14

Suspect A is actually telling the truth and they describe the events of a certain evening with confidence. After being asked to

do so, suspect A then retells the events of the same evening in the reverse order. What is this suspect relying on?
The inexperience of the interrogator


The ability to confuse the interrogator


The power of their memory


The power of their ability to lie
Chemistry
1 answer:
lorasvet [3.4K]3 years ago
7 0

It seems like the answer is C, you really just need to use the process of elimination.

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Answer:

E....H+

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What are the ionic bonds
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Explanation:

Ionic bonds are bonds formed as a result of the electrostatic attraction between two species.

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Hydrodistillation explain ????​
777dan777 [17]

Answer:

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4 0
3 years ago
Be sure to answer all parts. What is the [H3O+] and the pH of a buffer that consists of 0.26 M HNO2 and 0.89 M KNO2? (K, of HNO2
Aleksandr-060686 [28]

Answer : The H_3O^+ ion concentration is, 1.12\times 10^{-3}M and the pH of a buffer is, 2.95

Explanation : Given,

K_a=7.1\times 10^{-4}

Concentration of HNO_2 (weak acid)= 0.26 M

Concentration of KNO_2 (conjugate base or salt)= 0.89 M

First we have to calculate the value of pK_a.

The expression used for the calculation of pK_a is,

pK_a=-\log (K_a)

Now put the value of K_a in this expression, we get:

pK_a=-\log (7.1\times 10^{-4})

pK_a=4-\log (7.1)

pK_a=3.15

Now we have to calculate the pH of the solution.

Using Henderson Hesselbach equation :

pH=pK_a+\log \frac{[Salt]}{[Acid]}

pH=pK_a+\log \frac{[KNO_2]}{[HNO_2]}

Now put all the given values in this expression, we get:

pH=3.15+\log (\frac{0.89}{0.26})

pH=2.95

The pH of a buffer is, 2.95

Now we have to calculate the H_3O^+ ion concentration.

pH=-\log [H_3O^+]

2.95=-\log [H_3O^+]

[H_3O^+]=1.12\times 10^{-3}M

The H_3O^+ ion concentration is, 1.12\times 10^{-3}M

4 0
3 years ago
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