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steposvetlana [31]
3 years ago
8

A 1350 kg car travels at 12 m/s. What is it's kinetic energy

Physics
1 answer:
Lana71 [14]3 years ago
5 0

Hello!

A 1350 kg car travels at 12 m/s. What is it's kinetic energy ?

We have the following data:  

m (mass) = 1350 kg  

v (velocity) = 12 m/s  

KE (kinetic Energy) = ? (in Joule)  

Formula to calculate kinetic energy:

\boxed{KE = \dfrac{1}{2} *m*v^2}

Solving:

KE = \dfrac{1}{2} *m*v^2

KE = \dfrac{1}{2} *1350*12^2

KE = \dfrac{1}{2} *1350*144

KE = \dfrac{194400}{2}

\boxed{\boxed{KE = 97200\:Joule}}\:or\:\boxed{\boxed{KE = 97.2\:kJ}}\Longleftarrow(kinetic\:energy)\:\:\:\:\:\:\bf\blue{\checkmark}

_______________________

\bf\green{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}\:\:\ddot{\smile}

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The time spent in the air by the ball at the given momentum is 6.43 s.

The given parameters;

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The time of motion of the ball is calculated as follows;

t = \frac{\Delta P}{F} \\\\t = \frac{0.9 - 0}{0.14} \\\\t = 6.43 \ s

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A diffraction pattern forms when light passes through a single slit. The wavelength of the light is 691 nm. Determine the angle
expeople1 [14]

Explanation:

Given that,

Wavelength of the light, \lambda=691\ nm=691\times 10^{-9}\ m

(a) Slit width, a=3.8\times 10^{-4}\ m

The angle that locates the first dark fringe is given by :

sin\theta=\dfrac{\lambda}{a}

sin\theta=\dfrac{691\times 10^{-9}}{3.8\times 10^{-4}}

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(b) Slit width, a=3.8\times 10^{-6}\ m

The angle that locates the first dark fringe is given by :

sin\theta=\dfrac{\lambda}{a}

sin\theta=\dfrac{691\times 10^{-9}}{3.8\times 10^{-6}}

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