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3 years ago

A 1350 kg car travels at 12 m/s. What is it's kinetic energy

Physics

1 answer:

Lana71 [14]3 years ago

5 0

Hello!

A 1350 kg car travels at 12 m/s. What is it's kinetic energy ?

We have the following data:

m (mass) = 1350 kg

v (velocity) = 12 m/s

KE (kinetic Energy) = ? (in Joule)

Formula to calculate kinetic energy:

$\boxed{KE = \dfrac{1}{2} *m*v^2}$

Solving:

$KE = \dfrac{1}{2} *m*v^2$

$KE = \dfrac{1}{2} *1350*12^2$

$KE = \dfrac{1}{2} *1350*144$

$KE = \dfrac{194400}{2}$

$\boxed{\boxed{KE = 97200\:Joule}}\:or\:\boxed{\boxed{KE = 97.2\:kJ}}\Longleftarrow(kinetic\:energy)\:\:\:\:\:\:\bf\blue{\checkmark}$

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The circumference of a circle is 12π meters. find the circle diameter.

Veseljchak [2.6K]

The circumference of a circle is 2*pi*r=C so plugging in numbers we have
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Diameter = 12meters

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3 years ago

A 50-cm wire placed in an east-west direction is moved horizontally to the north with a speed of 2.0 m/s. the horizontal compone

Strike441 [17]

When a wire is moved inside uniform magnetic field then its free electrons will experience magnetic force on it due to which wire will have potential difference at its ends.

Now here we will have magnetic field due to earth and wire is moving in this constant field so induced emf is given by formula

$EMF = v.(B x L)$

given that

$B = 25\mu Tj - 50\mu Tk$

$v = 2 m/s j$

$L = 0.50 m (-i)$

now by using the above formula we will have

$EMF = 2(j) .(25\mu j - 50\mu k) x (-0.50 i)$

$EMF = 2(j) .(12.5\mu k + 25\mu j)$

$EMF = 50 \mu Volts$

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3 years ago

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The length of the adult mosquito is typically between 3.0 mm and 6.0 mm. The smallest known mosquitoes are around 2.5 mm, and th

FrozenT [24]

0.74in

Explanation:

Given parameters:

length range of adult mosquito = 3.0 - 6.0mm

Smallest mosquito = 2.5mm

Largest mosquito = 19mm

Average mass range = 3.0 - 5.0mg

Unknown:

Length of largest known mosquito in inches = ?

Solution;

The length is the longest dimension. It is how long a body is.

The problem here is converting from mm to inches;

The length of the longest mosquito which is the largest is 19mm

19mm to inches;

1mm = 0.039inches

19mm = 19mm x $\frac{0.039in}{1mm}$ = 0.74in

learn more:

Scale brainly.com/question/570757

#learnwithBrainly

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3 years ago

Two long straight wires are parallel and 8.6 cm apart. They are to carry equal currents such that the magnetic field at a point

Neko [114]

Answer:

(a) The current should be in opposite direction

(b) The current needed is 39.8 A

Explanation:

Part (a)

Based, on right hand rule, the current should be in opposite direction

Part (b)

given;

strength of magnetic field, B = 370 µT

distance between the two parallel wires, d = 8.6 cm

$B = \frac{\mu_oI}{2\pi R}$

At the center, the magnetic field strength is twice

$B_c = 2(\frac{\mu_oI}{2\pi R}) =\frac{ \mu_oI}{\pi R}$

R = d/2 = 8.6/2 = 4.3 cm = 0.043 m

$B_c = \frac{ \mu_oI}{\pi R}\\\\I = \frac{B_c\pi R}{\mu_o} = \frac{370 *10^{-6}* \pi *0.043}{4\pi *10^{-7}}\\\\I = 39.8 \ A$

Therefore, current needed is 39.8 A

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3 years ago

The centripetal force acting on the space shuttle

tamaranim1 [39]

Answer:

(4) weight

Explanation:

The centripetal force acting on the space shuttle in orbit is given by:

$F=m\frac{v^2}{r}$

where

m is the mass of the shuttle

v is the tangential speed of the shuttle

r is the radius of its circular orbit

When the shuttle orbits the Earth, the centripetal force that keeps the shuttle in circular motion is given by the gravitational attraction between the shuttle and the Earth, which corresponds to the weight of the shuttle, and it is given by:

$F=G\frac{Mm}{r^2}$

where

G is the gravitational constant

M is the Earth's mass

And this force, therefore, corresponds to the centripetal force.

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3 years ago

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