Explanation:
It is given that,
Let q₁ and q₂ are two small positively charged spheres such that,
.............(1)
Force of repulsion between the spheres, F = 1 N
Distance between spheres, d = 2 m
We need to find the charge on the sphere with the smaller charge. The force is given by :



............(2)
On solving the system of equation (1) and (2) using graph we get,


So, the charge on the smaller sphere is 11.6 micro coulombs. Hence, this is the required solution.
Answer:
No de español muy bien por favor pregúntalo en inglés
Explanation:
Answer: Speed = 4m/s
Strength = 7.1T
Explanation: P= 4.0w
N = 1.0
V= ?
Power = force x velocity
Velocity = power/ force
V= 4.0w/1.0N
V = 4m/s
Strength of the magnetic field
B = √PR / lv
Where; l = length 10cm
R= 2.0
P= 4.0w
V= 4m/s
B = √ (4.0w) × (2.0) / (10cm) × (4m/s)
B = 7.1T
Answer:
Explanation:
If one assume that each turn is like a strand of electromagnet, which can then be added up. Therefore, increase in the number of turns will yield to increase in the magnetic strength. Also if the current increases, then there will be increase in the magnetic field strength.
From Ohm's law
V = IR
I = V/R
That is a direct increase in voltage will lead to increase in current.
Increase the voltage of the battery and increases the number of turns of the coil. Will suit the situation
If the crate is moving along the floor in the same direction with a constant speed, it is in dynamic equilibrium. Equilibrium means there is no net force acting on the crate.
Since there is no net force on the crate, there must be a friction force on the crate equal in magnitude and opposite in direction to the applied horizontal force. Therefore the force of friction acting on the crate is 100N.