QUICK!! What class of lever is this image depicting?
2 answers:
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Answer:
(A). The work done is .
(B). The potential of the starting point with respect to the endpoint is 357.14 V.
(C). The magnitude of E is 5952.38 N/C.
Explanation:
Given that,
Charge = 4.20 nC
Distance = 6.00 cm
Kinetic energy
The particle start from rest.
So, the initial kinetic energy i zero.
(A). We need to calculate the work by the electric force
Using formula of work done
Put the value into the formula
The work done is .
(B). We need to calculate the potential of the starting point with respect to the endpoint
We know that.
Change in potential energy = change in kinetic energy
So,
Using formula of potential
Put the value into the formula
The potential of the starting point with respect to the endpoint is 357.14 V.
(C). We need to calculate the magnitude of E
Using formula of work done
....(I)
Using formula of force
Put the value in the equation (I)
Put the value into the formula
The magnitude of E is 5952.38 N/C.
Hence, This is the required solution.