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3 years ago

1. height of tower when stone dropped from it reaches ground in 10s is

Physics

1 answer:

Arada [10]3 years ago

7 0

Answer:

490.5 m

Explanation:

we can use the formula s = ut + ½at^2

s= displacement (height of tower)

initial velocity u = 0 m/s

acceleration a = take 9.81 ms-2 (acceleration due to gravity, which is a constant. depending on the given instructions of the question, it may not be exactly 9.81. Some take 10, some take 9.80665)

time t =10s

s = 0t + 1/2 (9.81)(10)^2

s = 490.5 m

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3 years ago

A 0.12 kg body undergoes simple harmonic motion of amplitude 8.5 cm and period 0.20 s. (a) What is themagnitude of the maximum f

Neporo4naja [7]

Answer:

a)F=698.83 N

b)K=8221.56 N/m

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time period ,T = 0.2 s

We know that

$T=\dfrac{2\pi}{\omega}$

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3 0

4 years ago

Help me please!! 15points

Romashka-Z-Leto [24]

Explanation:

Acceleration is the change in speed over change in time.

a = Δv / Δt

a. The car's acceleration is:

a = (80 km/h − 0 km/h) / 10 s

a = 8 km/h/s

So every second, the speed increases by 8 km/h.

b. The cyclist's acceleration is:

a = (16 m/s − 4.0 m/s) / 5.6 s

a = 2.1 m/s²

c. The stone's speed is:

10.0 m/s² = (v − 0 m/s) / 3.5 s

v = 35 m/s

d. The time is:

1.6 m/s² = (10 m/s − 0 m/s) / t

t = 6.3 s

4 0

4 years ago

1. height of tower when stone dropped from it reaches ground in 10s is​

1. height of tower when stone dropped from it reaches ground in 10s is