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3 years ago

1. height of tower when stone dropped from it reaches ground in 10s is

Physics

1 answer:

Arada [10]3 years ago

7 0

Answer:

490.5 m

Explanation:

we can use the formula s = ut + ½at^2

s= displacement (height of tower)

initial velocity u = 0 m/s

acceleration a = take 9.81 ms-2 (acceleration due to gravity, which is a constant. depending on the given instructions of the question, it may not be exactly 9.81. Some take 10, some take 9.80665)

time t =10s

s = 0t + 1/2 (9.81)(10)^2

s = 490.5 m

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A solid sphere has a radius of 0.200 m and a mass of 150.0 kg. how much work is required to get the sphere rolling with an angul

Allisa [31]

Here in this case we can use work energy theorem

As per work energy theorem

Work done by all forces = Change in kinetic Energy of the object

Total kinetic energy of the solid sphere is ZERO initially as it is given at rest.

Final total kinetic energy is sum of rotational kinetic energy and translational kinetic energy

$KE = \frac{1}{2}Iw^2 +\frac{1}{2} mv^2$

also we know that

$I = \frac{2}{5}mR^2$

$w= \frac{v}{R}$

Now kinetic energy is given by

$KE = \frac{1}{2}(\frac{2}{5}mR^2)w^2 +\frac{1}{2} m(Rw)^2$

$KE = \frac{1}{5}mR^2w^2 +\frac{1}{2} mR^2w^2$

$KE = \frac{7}{10}mR^2w^2$

$KE = \frac{7}{10}*150*(0.200)^2(50)^2$

$KE = 10500 J$

Now by work energy theorem

Work done = 10500 - 0 = 10500 J

So in the above case work done on sphere is 10500 J

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3 years ago

By what factors does the speed of the elctron exceed that of the proton?

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Answer:

» An electron is lighter than a proton.

explanation:

${ = \: \sf{an \: electron \: has \: formula \: \: }}{ \bf{ {}^{0}_{ - 1}e }}$

hence it's mass number is zero

${ = \: \sf{an \: electron \: is \: helium \: particle \: \: }}{ \bf{ {}^{4} _{2}He }}$

hence it's mass number is 4

Therefore, proton is heavier than electron

» An electron has a small charge magnitude than a proton.

Explanation:

An electron has charge of -1 while proton has charge of +2, therefore electron is less deflected by any energetic fields than a proton

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An observer stands 24.7 m behind a marksman practicing at a rifle range. The marksman fires the rifle horizontally, the speed of

GaryK [48]

Explanation:

The given data is as follows.

Velocity of bullet, $c_{p}$ = 814.8 m/s

Observer distance from marksman, d = 24.7 m

Let us assume that time necessary for report of rifle to reach the observer is t and will be calculated as follows.

t = $\frac{24.7}{343}$ (velocity in air = 343 m/s)

= 0.072 sec

Now, before the observer hears the report the distance traveled by the bullet is as follows.

$d_{b} = c_{b} \times t$

= $814.8 \times 0.072$

= 58.66

= 59 (approx)

Thus, we can conclude that each bullet will travel a distance of 59 m.

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3 years ago

Determine the velocity of a car that travels 28km in 2.2 hours

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Answer:

<h2>velocity = 12.73 km/hr.</h2><h2 />

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velocity = distance / time

= 28 km

2.2 hr

= 12.73 km/hr.

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3 years ago

1. height of tower when stone dropped from it reaches ground in 10s is​

1. height of tower when stone dropped from it reaches ground in 10s is