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3 years ago

Which feature of the evaporating dish makes it effective in the evaporation process

Chemistry

2 answers:

Umnica [9.8K]3 years ago

5 0

Answer:

The precise fit on the ring stand. The ability to hold more substance than a test tube. A shallow bottom to increase the surface area of a liquid, leaving the solid behind.

Explanation:

Q and A!

How does an evaporating dish work?

Evaporating dishes are used to evaporate excess solvents – most commonly water – to produce a concentrated solution or a solid precipitate of the dissolved substance. ... The dish is heated with a Bunsen burner, until only stable precipitate remains, which contains the silica content.

What does a evaporating dish looks like?

The evaporating dish is a small bowl with a spout, usually made of porcelain or borosilicate glass. As its name suggests, it is commonly used to evaporate solvents in a sample. The evaporating dishes we encounter in a chemistry lab usually accommodate small samples.

<h2><u><em>Good Look On Your Assignment- Joshua Amachee :) </em></u></h2>

tigry1 [53]3 years ago

4 0

The precise fit on the ring stand. The ability to hold more substance than a test tube. A shallow bottom to increase the surface area of a liquid, leaving the solid behind.

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7g of gold is heated from 17 degrees C to 42 degrees C. How much energy (heat) was used? The specific heat capacity of gold is .

wel

Heat needed=mcθ
=7×0.031×(42-17)
=5.425cal

7 0

3 years ago

The initial pressure of a mixture of C6H6 and an excess of H2 in a rigid vessel is 1.21 atm. A catalyst is introduced. After the

KengaRu [80]

Answer:

mole fraction of C6H6 = 0.613 atm

Explanation:

The equation for this reaction is :

$C_6H_6 _{(g)} + 3H_2_{(g)} \to C_6H_{12}_{(g)}$

Initial P₁ P₂ 0

Final 0 P₂ -P₁/2 P₁

After completion of the reaction;

P₁ + P₂ = 1.21 atm ----- (1)

P₂ - P₁/2 + P₁ = 0.839 atm

P₂ + P₁/2 = 0.839 atm ----- (2)

Subtracting (2) from (1); we have:

P₁/2 = 0.371

P₁ = 0.742 atm

From(1)

P₁ + P₂ = 1.21 atm

0.742 atm + P₂ = 1.21 atm

P₂ = 1.21 atm - 0.742 atm

P₂ = 0.468 atm

Thus, the partial pressure of C6H6 = 0.742 atm

∴

Partial pressure = Total pressure × mole fraction of C6H6

mole fraction of C6H6 = Partial pressure / Total pressure

mole fraction of C6H6 = 0.742 atm / 1.21 atm

mole fraction of C6H6 = 0.613 atm

5 0

3 years ago

PLEASE HELP!!

omeli [17]

Answer:

8/3 hours

Explanation:

12.5/100=1/8, 1/8*2=2/8=1/4 1/4*2=1/2 1/2*2 = 1 (whole)

we multiplyed 1/8 by two three times to get 1 so 8/3 hours is the answer

by the way i'm in 6th grade

3 0

3 years ago

Read 2 more answers

Scoring scheme: 3-3-2-1 using the ion concentration values in cells #3 & #5 in the expression, ecell#5 - ecell#3 = -(0.0257/

nexus9112 [7]

I made a fake account and everything but still no answer. Brainly done got me [email protected] up

3 0

3 years ago

When the following oxidation-reduction occurs, what is the balanced reduction half-reaction after the electrons in both half rea

Lostsunrise [7]

Answer : The balanced reduction half-reaction is:

$3Cu^{2+}+6e^-\rightarrow 3Cu$

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

The given balanced redox reaction is :

$Al(s)+Cu^{2+}(aq)\rightarrow Al^{3+}(aq)+Cu(s)$

The half oxidation-reduction reactions are:

Oxidation reaction : $Al\rightarrow Al^{3+}+3e^-$

Reduction reaction : $Cu^{2+}+2e^-\rightarrow Cu$

In order to balance the electrons, we multiply the oxidation reaction by 2 and reduction reaction by 3 and then added both equation, we get the balanced redox reaction.

Oxidation reaction : $2Al\rightarrow 2Al^{3+}+6e^-$

Reduction reaction : $3Cu^{2+}+6e^-\rightarrow 3Cu$

The balanced redox reaction will be:

$2Al(s)+3Cu^{2+}(aq)\rightarrow 2Al^{3+}(aq)+3Cu(s)$

Thus, the balanced reduction half-reaction is:

$3Cu^{2+}+6e^-\rightarrow 3Cu$

6 0

3 years ago