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ddd [48]
3 years ago
6

Mars moves in an elliptical orbit around the sun, and the mass of mars is much less than the mass of the sun. at the instant sho

wn above, mars is getting farther away from the sun. how does this affect the potential energy of the mars-sun system and the magnitude of mars angular momentum with respect to the sun
Physics
1 answer:
Bess [88]3 years ago
4 0
I believe the answer would be that the system potential energy will increase; while the Mar's angular momentum will remain the same. 
Mars rotates on its axis, completing one revolution every 24.6 hours. The axis of mars is tilted at 25 degrees and 12 minutes relative to its orbital plane about the Sun. This produces seasons on the surfaces of Mars, similar to the seasons on Earth. 
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Which of the following is an impact of trampling of beach grass by humans and vehicles?
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Increase in sea water pollution
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The gravitational attraction between two objects increases if
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Jessica is running a 10K. She alternates between running and walking each kilometer. She runs at a rate of 1 kilometer every 5 m
saveliy_v [14]

Answer:

c.100 minutes

Explanation:

Total distance = 10 km

Runs for 1 km every 5 minutes

walks 1 km every 15 min

She alternates between walking and running  so,  Jessica will walk 5 km and run 5 Km

Time taken by Jessica for walking : 5 km

Time taken to walk 1 km=5 minutes

Time taken to walk 5 km

=> 5 X 5

=>25 minutes

Time taken by Jessica for Running : 5km

Time taken to run 1 km = 15 minutes

 

=> 5 X 15

=>75 minutes

Total time taken   = Time taken by Jessica for walking + Time taken by Jessica for Running

=>25 minutes +75 minutes

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8 0
3 years ago
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In a football game, the running back takes a handoff and begins running toward midfield at 3.21 yards/s . As he moves through hi
Inessa [10]

Given Information:

Initial speed = u = 3.21 yards/s

Acceleration = α  = 1.71 yards/s²

Final speed = v = 7.54 yards/s

Required Information:

Distance = s = ?

Answer:

Distance = s = 13.61

Explanation:

We are given the speeds and acceleration of the runner and we want to find out how much distance he covered before being tackled.

We know from the equations of motion,

v² = u² + 2αs

Where u is the initial speed of the runner, v is the final speed of the runner, α is the acceleration of the runner and s is the distance traveled by the runner.

Re-arranging the above equation for distance yields,

2αs = v² - u²

s = (v² - u²)/2α

s = (7.54² - 3.21²)/2×1.71

s = 46.55/3.42

s = 13.61 yards

Therefore, the runner traveled a distance of 13.61 yards before being tackled.

8 0
3 years ago
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