Newton's second law allows calculating the response for the person's acceleration while leaving the trampoline is:
-4.8 m / s²
Newton's second law says that the net force is proportional to the product of the mass and the acceleration of the body
F = m a
Where the bold letters indicate vectors, F is the force, m the masses and the acceleration
The free body diagram is a diagram of the forces without the details of the body, in the attached we can see the free body diagram for this system
-W = m a
Whera is the trampoline force
Body weight is
W = mg
We substitute
- mg = ma
a =
Let's calculate
a = 
a = -4.8 m / s²
The negative sign indicates that the acceleration is directed downward.
In conclusion using Newton's second law we can calculate the acceleration of the person while leaving the trampoline is
-4.8 m / s²
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Answer:
Principle of conservation of linear momentum is state as provided no external force acts on a system of colliding bodies the total linear momentum of the bodies (in a given direction) remains constant
Answer;
B. Mass and energy are equivalent.
Explanation;
-Each of the letters of E = mc2 stands for a particular physical quantity.
E is the energy, m is the mass and c is the speed of light (m/s)
Energy = mass x the speed of light squared
-The equation E=mc2 explains nuclear fusion, how matter can be destroyed and converted to energy and energy can be converted back to mass. It explains the atomic energy produced by nuclear power plants and the atomic energy released by atomic bombs.
-The equation tells us that mass and energy are related, and, in those rare instances where mass is converted totally into energy, how much energy that will be.
The transition zone between the crust and mantle is called as mohorovicic discontinuity.
The mohorovicic discontinuity was discovered by Andrija Mohorovicic in the year of 1909. The Moho lies at the depth of 35km beneath the continents and 8km beneath the oceanic crust. The Moho separates both the continental crust and the oceanic crust from underlying mantle. The Moho lies almost entirely within the lithosphere, only beneath the Mid Oceanic Ridge does it define lithosphere and asthenosphere boundary. Immediate above the Moho velocity of the P wave is 6km/sec and just below the Moho it becomes 8km/sec. Moho is characterised by up to 500km thick.
The Mohorovicic Discontinuity marks the lower limit of Earth's crust. It occurs at an average depth of about 8 kilometers beneath the ocean basins and 32 kilometers beneath continental surfaces. Mohorovicic was able to use his discovery to study thickness variations of the crust.
Mohorovicic discontinuity is the layer which is between the earth's crust and mantle. It's density ranges from 3.3 to 3.7.
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The calculated weight in newtons is 10 N.
Listed below is the data we will use:
Area A is where the pressure is P. Here are the details we were given:
A=1 cm2, P=101325 N/m, and w=?
Do the area conversion to square meters.
A=1cm2×1m2/1002cm2\s=1×10−4m2
From the definition of pressure, calculate the weight of the air column. In this instance, the air column's weight is determined by multiplying the atmospheric pressure by the air column's base area.
Fw = P atm A
= (101325N/m2) (1 10 4m2)
= 10N
The complete question is - Imagine a square column of the atmosphere, 1 cm on a side, that extends all the way to the top of the atmosphere. How much does this column of air weigh in newtons?
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