Answer:
t = 123.59s
Explanation:
For the launch pad section:
Vf = Vo + a*t where Vo=0.
Vf = 35*25 = 875m/s
The distance traveled during the launch:

Now the projectile motion, we know that its initial speed is the speed calculated previously and the initial height is the y-component of the previously calculated distance.

where d= 10937.5m; Vo=875m/s.
Solving for t:
t1 = -11.093s t2 = 98.59s
So, the total time of flight will be:

Answer:
Geology Notes
1 Veryovkina Cave 2212[1] 13.5 km (8.4 mi)[1] Abkhazia / Georgia 43°23′52″N 40°21′37″E.
Answer:
The maximum wavelength is 492 nm.
Explanation:
Given that,
Angular separation 
Suppose a telescope with a small circular aperture of diameter 2.0 cm.
We need to calculate the maximum wavelength
Using formula of angular separation


Put the value into the formula

For small angle 



Hence, The maximum wavelength is 492 nm.
If they lose an electron, that means they become more positive since an electron is negatively charged. So the answer is ‘positive’