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monitta
3 years ago
13

If you add two velocity vectors going in opposite directions, will the resultant vector be smaller or larger than the vectors yo

u are adding?
Choose the correct answer with the correct reasoning.

Question 11 options:

smaller, because the vectors are added to each other and increase the velocity


larger, because the vectors are added to each other and increase the velocity


smaller, because part of the velocities cancel each other out


larger, because the part of the velocities cancel each other out
Physics
2 answers:
11111nata11111 [884]3 years ago
7 0

smaller, because the part of the velocities cancel each other out

Lemur [1.5K]3 years ago
4 0

Explanation:

If two vectors going in opposite directions and we add them, the resultant is given by the sum of vectors as :

R=\sqrt{A^2+B^2+2AB\ cos(180)}, cos (180) = -1

R=A+(-B)

If the vectors are in same directions, the resultant is equal to the sum of vectors. Here, the resultant of two vectors is smaller because the part of the velocities cancel out each other. Hence, the correct option is (c).

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A motorcycle is following a car that is traveling at constant speed on a straight highway. Initially, the car and the motorcycle
ra1l [238]

Answer:

a) t = 4.16 s

b) x = 141.51 m

Explanation:

Given

v = 21.5 m/s

x0 = 52.0 m

a = 6.0 m/s²

a) Motorcycle

x = v0*t + (a*t²/2)

x = 21.5t + (6*t²/2)

x = 21.5t + 3t²   <em>(I)</em>

Car

x = x0 + v0*t

x = 52 + 21.5t  <em>(II)</em>

<em />

then we can apply <em>I = II</em>

21.5t + 3t² = 52 + 21.5t

⇒ 3t² = 52

⇒ t = 4.16 s

b) We can use <em>I</em> or <em>II</em>, then

x = 52 + 21.5*(4.16)

⇒ x = 141.51 m

8 0
3 years ago
A team of dogs accelerates a 290kg dogsled from 0 to 6.0m/s in 3.0 s. Assume that the acceleration is constant.Part AWhat is the
Mademuasel [1]

Answer:

(a) a=2m/sec^2

(b) 5220 j

(c) 1740 watt

(d) 3446.66 watt

Explanation:

We have given mass m = 290 kg

Initial velocity u = 0 m/sec

Final velocity v = 6 m/sec

Time t = 3 sec

From first equation of motion

v = u+at

So a=\frac{v-u}{t}=\frac{6-0}{3}=2m/sec^2

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F = ma

So force will be F=290\times 2=580N

(b) From second equation of motion we know that

s=ut+\frac{1}{2}at^2=0\times 3+\frac{1}{2}\times 2\times 3^2=9m

We know that work done is given by

W = F s = 580×9 =5220 j

(c) Time is given as t = 3 sec

We know that power is given as

P=\frac{W}{t}=\frac{5220}{3}=1740Watt

(d) Time t = 1.5 sec

So P=\frac{W}{t}=\frac{5220}{1.5}=3466.66Watt

5 0
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Answer pls will give 20 points per person
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Answer: question 1 is b I believe

Explanation:

every action has an opposite reaction

7 0
3 years ago
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