This the answer <span>Often, a law can be expressed in the form of a single mathematical equation. Laws and theories are similar in that they are both scientific statements that result from a tested hypothesis and are supported by scientific evidence. ... A theory, in contrast, is a less concise statement of observed phenomena. i hope this help </span>
Answer:
<h2>D) S increases because at all times Rock X falls with a greater speed than Rock Y</h2>
Explanation:
As we know that Stone X is dropped first and then after some time stone Y is dropped
Now we have
similarly for Y
now the relative acceleration of two stones while they are in air is ZERO
also we know from above equations
so the separation between two stones will keep on increasing as the speed of X is more than the speed of Y
Gravitational force between 2 objects . . .
F = G · m₁ · m₂ / D²
-- You said that F = 3.5 x 10²² Newtons.
-- G = the gravitational constant = 6.67 x 10⁻¹¹ N m² / kg²
-- You want to find D .
F = G · m₁ · m₂ / D²
Multiply each side by D² . . . D² · F = G · m₁ · m₂
Divide each side by F . . . D² = G · m₁ · m₂ / F
So finally . . . D = √(G · m₁ · m₂ / F )
D = √(6.67 x 10⁻¹¹ N·m²/kg² · Earth mass · Sun mass / 3.5 x 10²² N)
<em>D = 4.37 x 10⁻¹⁷ · √(Earth mass · Sun mass) </em> meters
Answer
given,
mass of people = 65 kg
number of people =
diameter of the merry-go-round = 4.2 m
radius = 2.1 m
angular velocity = 0.8 rad/s
moment of inertia = 1760 kg m²
Using the law of conservation of angular momentum, we have
L₁= L₂
I₁ω₁ =I₂ω₂
I₁ω₁= ( I₁+ 4 m r²)ω²
( 1760 x 0.8) = ( 1760 + 4 x 65 x 2.12)ω²
1408 = 2311.2 ω²
ω² = 0.609
ω = 0.781 rad/s
b) If the people jump of the merry-go-round radially, they exert no torque.
hence, it will not change the angular momentum of the merry-go-round. It will continue to move with the same ω .
