Answer and explanation:
A) An ideal fuel must:
- easy to transport and storage.
- have a high calorific value.
B) The <em>calorific value</em> for a fuel is the amount of heat - measured in Joules- which is produced during the complete combustion of the fuel. It is expressed in Joules per Kg of fuel (J/kg).
C) From the data:
mass of fuel = 2 kg
heat produced = 48,000 KJ
We calculate the calorific value by dividing the heat produced by the mass of fuel, as follows:
calorific value = heat produced/mass of fuel = (48,000 KJ)/(2 kg)= 24,000 kJ/kg
Since 1 KJ= 1000 J, we can express the calorific value in J/kg as follows:
24,000 kJ/kg x 1000 J/1 kJ = 2.4 x 10⁷ J/kg
Answer:
Explanation:
Since the <em>rate constant</em> has units of <em>s⁻¹</em>, you can tell that the order of the reaction is 1.
Hence, the rate law is:
![r=d[A]/dt=-k[A]](https://tex.z-dn.net/?f=r%3Dd%5BA%5D%2Fdt%3D-k%5BA%5D)
Solving that differential equation yields to the well known equation for the rates of a first order chemical reaction:
![[A]=[A]_0e^{-kt}](https://tex.z-dn.net/?f=%5BA%5D%3D%5BA%5D_0e%5E%7B-kt%7D)
You know [A]₀, k, and t, thus you can calculate [A].
![[A]=0.548M\times e^{-3.6\cdot 10^{-4}/s\times99.2s}](https://tex.z-dn.net/?f=%5BA%5D%3D0.548M%5Ctimes%20e%5E%7B-3.6%5Ccdot%2010%5E%7B-4%7D%2Fs%5Ctimes99.2s%7D)
![[A]=0.529M](https://tex.z-dn.net/?f=%5BA%5D%3D0.529M)
The answer is D.
The air inside the bubbles is gas and the solid forms the bubble.
Answer: C6H6
Explanation: Molecular Formula is the molecular mass divided by the empirical formula mass of CH which is C 12and H is 1 so 12 + 1= 13 g CH
Solution:
78.11 g CH / 13 g CH = 6
