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Korvikt [17]
3 years ago
13

Two particles of a gas collide. Why is this considered an elastic collision? (1 point)

Physics
2 answers:
dezoksy [38]3 years ago
7 0
I don’t know really really I don’t know
RSB [31]3 years ago
5 0

They bounce off each other, conserving energy and momentum.

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What types of sound waves diffract more than others
cricket20 [7]

Answer:

Infrasound

but the longer the wavelength of a soundwave, the more it diffracts

Explanation:

7 0
3 years ago
Why does self inductance acts as electrical inertia?​
Taya2010 [7]

Answer:

self-indulgence of coil is the property by virtue of wich is tends to maintain magnatic flux link with it and opposed any any change in the flux inducing current in it

8 0
3 years ago
Express the number in scientific notation: 4/100
ankoles [38]

Answer:

4*10^-2

Explanation:

for the scientific notation the first number must be between 1 and 10, so in this case it is 4. 4/100 is also equal to 0.04, and if we could the number of places before 4, there are two, therefore 4 times 10 to the power of -2

5 0
3 years ago
The wheel on an upside-down bicycle moves through 18.0 rad in 5.39 s. What is the wheel’s angular acceleration if its initial an
Elden [556K]

Explanation:

Formula to calculate angular acceleration is as follows.

   \Delta (\theta) = \frac{1}{2} \alpha \Delta t^{2} + \omega_{1} \Delta t

or,      \alpha = \frac{2(\Delta (\theta) - \omega_{1} \Delta t)}{\Delta t^{2}}

Putting the given values into the above formula as follows.

    \alpha = \frac{2(\Delta (\theta) - \omega_{1} \Delta t)}{\Delta t^{2}}

                = \frac{2(18.0 rad - 2.5 rad/s \times 5.30 s)}{(5.39)^{2}}    

                = 0.326 rad/s^{2}

Thus, we can conclude that the wheel’s angular acceleration if its initial angular speed is 2.5 rad/s is 0.326 rad/s^{2}.

5 0
3 years ago
The amusement park ride shown above takes riders straight up a tall tower and then releases an apparatus holding seats. This app
Natasha2012 [34]

The gravitational force on the rider is:

- Way up: equal to mg

- Way down: equal to mg

Explanation:

The choices are missing: find them in the attached figure.

The force of gravity acting on a body is a force directed downward (towards the Earth's centre) and whose magnitude is

F=mg

where

m is the mass of the body

g is the acceleration due to gravity

The value of g is approximately constant near the Earth's surface and it is

g=9.8 m/s^2

During the ride, the mass of the rider, m, remains constant. This means that the magnitude of the gravitational force, mg, exerted on the rider remains constant during the rider.

Therefore, the correct answer is

- Way up: equal to mg

- Way down: equal to mg

Learn more about force of gravity:

brainly.com/question/1724648

brainly.com/question/12785992

#LearnwithBrainly

7 0
3 years ago
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