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White raven [17]
3 years ago
12

What are the 7 clues that a chemical change has occurred

Physics
1 answer:
Umnica [9.8K]3 years ago
8 0

Answer:

Gas Bubbles Appear,

Formation of a Precipitate,

Color Change,

Temperature Change,

Production of Light,

Volume Change,

Change in Smell or Taste

Explanation:

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A 4.0-kg object has 72 J of kinetic energy.<br> Determine its speed.
Svetlanka [38]

Answer:

6m/s

Explanation:

v = sqrt of 2KE/m

Where:

KE = kinetic energy

m = mass of a body

v = velocity of a body

= sqrt of 2(72)/4

= sqrt of 144/4

= sqrt of 36

= 6m/s

8 0
2 years ago
8 N to the left , and 4 N to the right. Find the net force. Is this balanced?
alukav5142 [94]

Explanation:

12N by first law of newton is net force after colloision

7 0
2 years ago
1.
Harlamova29_29 [7]
1.renewable energy
2.renewable energy
3.Turning off the lights when you are not in a room
4.conservation of energy
5.Driving an SUV
6.stored energy
7.Always from one side to another
8.use our energy resources wisely
9.conservation of energy
10.by either moving liquids or moving air currrents
11.potential energy
12.radiation
13.insulators
14.radiation
15.Evaporation
16.Thermal energy moves to an object with less heat.
17.Burning your finger on a hot match
18.potential energy
19.Energy is never being created or destroyed.
20.touching each other
7 0
3 years ago
Read 2 more answers
Suppose an automobile has 2000-joules of kinetic energy. when it moves at twice the speed, what will be its kinetic energy? what
NeX [460]

Answer:

K.Eₓ = 4 K.E

K.Eₓ = 9 K.E

Explanation:

Th formula for the kinetic energy of a body is given as follows:

K.E = \frac{1}{2}mv^2\\   ---------------equation (1)

where,

K.E = Kinetic Energy of Automobile

m = mass of automobile

v = speed of automobile

For twice speed:

vₓ = 2v

then,

K.E_{x} = \frac{1}{2}mv_{x}^2\\K.E_{x} = \frac{1}{2}m(2v)^2\\K.E_{x} = 4\frac{1}{2}mv^2\\

using equation (1):

<u>K.Eₓ = 4 K.E</u>

For thrice speed:

vₓ = 3v

then,

K.E_{x} = \frac{1}{2}mv_{x}^2\\K.E_{x} = \frac{1}{2}m(3v)^2\\K.E_{x} = 9\frac{1}{2}mv^2\\

using equation (1):

<u>K.Eₓ = 9 K.E</u>

6 0
3 years ago
11. एक समान चुम्बकीय क्षेत्र में लम्बवत प्रवेश करने वाले किसी आवेशित कण द्वारा प्राप्त वृत्तीय पथ की
mojhsa [17]

Answer:

<h2> r=mv/Be</h2>

Explanation:

If a positive charge enters a magnetic field at 90 degrees the charge is deflected in a circular path by a force that acts perpendicular to it in line with Flemings right-hand rule

to derive the radius of the path of the charge we apply

F= mv^2/r=Bev

where

m= mass of the electronic charge

e=charge

B=magnetic field

v=average speed

r=radius

 

rearranging we have

r=mv^2/Bev

r=mv/Be

5 0
3 years ago
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