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harina [27]
3 years ago
8

Which is an example of a chemical change?

Physics
1 answer:
yulyashka [42]3 years ago
3 0
It’s burning wax. All of the other options are physical changes .
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The Celsius temperature scale is based on which of the following
Lapatulllka [165]
Freezing.................
6 0
3 years ago
how can you tell, as you walk close to a parked car, if it had been running recently? describe your reasoning in terms of energy
Blababa [14]
This question is probably referring to heat energy transferring from the car to its surroundings.
4 0
3 years ago
un astronauta cuya masa es 80kg permanece inmovil en el espacio exterior, al activar la unidad propulsora que lleva en la espald
beks73 [17]

Answer:

Explanation:

80(0) = 2(15) + (80-2)v

v = - 0.38 m/s

5 0
2 years ago
k) A stream of warm water is produced in a steady-flow mixing process by combining 1.0 kg s-1of cool water at 25°C with 0.8 kg s
Irina18 [472]

Answer:

T_ww = 43,23°C

Explanation:

To solve this question, we use energy balance and we state that the energy that enters the systems equals the energy that leaves the system plus losses. Mathematically, we will have that:

E_in=E_out+E_loss

The energy associated to a current of fluid can be defined as:

E=m*C_p*T_f

So, applying the energy balance to the system described:

m_CW*C_p*T_CW+m_HW*C_p*T_HW=m_WW*C_p*T_WW+E_loss

Replacing the values given on the statement, we have:

1.0 kg/s*4,18 kJ/(kg°C)*25°C+0.8  kg/s*4,18 kJ/(kg°C)*75°C=1.8 kg/s*4,18 kJ/(kg°C)*T_WW+30  kJ/s

Solving for the temperature Tww, we have:

(1.0 kg/s*4,18 kJ/(kg°C)*25°C+0.8 kg/s*4,18 kJ/(kg°C)*75°C-30 kJ/s)/(1.8 kg/s*4,18 kJ/(kg°C))=T_WW

T_WW=43,23 °C

Have a nice day! :D

6 0
3 years ago
Two point charges, Q1 and Q2, are separated by a distance R. If the magnitudes of both charges are tripled and their separation
stira [4]

Answer:

Remains the same

Explanation:

5 0
2 years ago
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