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harina [27]
3 years ago
8

Which is an example of a chemical change?

Physics
1 answer:
yulyashka [42]3 years ago
3 0
It’s burning wax. All of the other options are physical changes .
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About how much time elapses between high tides on the same day?
Pani-rosa [81]
There is about 12 hours
6 0
3 years ago
A car is driving away from a crosswalk. The formula d = t 2 + 2 t expresses the car's distance from the crosswalk in feet, d , i
Ede4ka [16]

Answer:

1) No, the car does not travel at constant speed.

2) V = 9 ft/s

3) No, the car does not travel at constant speed.

4) V = 5.9 ft/s

Explanation:

In order to know if the car is traveling at constant speed we need to derive the given formula. That way we get speed as a function of time:

V(t) = 2*t + 2   Since the speed depends on time, the speed is not constant at any time.

For the average speed we evaluate the formula for t=2 and t=5:

d(2) = 8 ft     and      d(5) = 35 ft

V_{2-5}=\frac{d(5)-d(2)}{5-2}=9 ft/s

Again, for the average speed we evaluate the formula for t=1.8 and t=2.1:

d(1.8) = 6.84 ft     and      d(2.1) = 8.61 ft

V_{1.8-2.1}=\frac{d(2.1)-d(1.8)}{2.1-1.8}=5.9 ft/s

4 0
3 years ago
HURRY PEASE what happens to current when there is a diode on the circuit and why?
kolbaska11 [484]

Answer:

The current can't 'split down the parallel branch, because the diode is reverse biased so is blocking the flow of current. So basically it's acting as an open circuit. Also when the current flows it wouldn't reduce the currents amount flow through the resistor.

Explanation:

6 0
3 years ago
An object has a mass of 60 kg. It decelerates from 50 m/s to 20 m/s when a resultant force of 300 N acts on it. For how long doe
Pavlova-9 [17]
  • Force=300N
  • Mass=60kg

Find Acceleration

\\ \rm\longmapsto F=ma

\\ \rm\longmapsto a=\dfrac{F}{m}

\\ \rm\longmapsto a=\dfrac{-300}{60}

\\ \rm\longmapsto a=-5m/s^2

Now

  • u=50m/s
  • v=20m/s

Using 1st equation of kinematics

\\ \rm\longmapsto v=u+at

\\ \rm\longmapsto t=\dfrac{v-u}{a}

\\ \rm\longmapsto t=\dfrac{20-50}{-5}

\\ \rm\longmapsto t=\dfrac{-30}{-5}

\\ \rm\longmapsto t=6

4 0
2 years ago
Calculate the average induced voltage between the tips of the wings of an airplane flying above East Lansing at a speed of 885 k
Yakvenalex [24]

Answer:

=0.855V

Explanation:

The induced voltage can be calculated using below expression

E =B x dA/dt

Where dA/dt = area

B= magnetic field = 6.90×10-5 T.

We were given speed of 885 km/h but we will need to convert to m/s for consistency of unit

speed = 885 km/h

speed = 885 x 10^3 m/hr

speed = 885 x 10^3/60 x60 m/s

speed = 245.8 m/s

If The aircraft wing sweep out" an area

at t= 50.4seconds then we have;

dA/dt = 50.4 x 245.8

= 123388.32m^2/s

Then from the expression above

E =B x dA/dt substitute the values of each parameters, we have

E = 6.90 x 10^-5 x 12388.32 V

E =0.855V

Hence, the average induced voltage between the tips of the wings is =0.855V

6 0
3 years ago
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