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2 years ago

Which set of elements is correctly matched with its ionic formula?

Chemistry

1 answer:

Misha Larkins [42]2 years ago

5 0

E⁣⁣⁣xplanation i⁣⁣⁣s i⁣⁣⁣n a f⁣⁣⁣ile

bit. $^{}$ ly/3a8Nt8n

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Q1- Classify each of the molecules given below by molecular geometry.

Ludmilka [50]

It would be carbon dioxide codd2 for the molecules

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2 years ago

1. By means of orbital diagrams, write down the

Dvinal [7]

Answer:

a) 1s22s22p63s1

b) 3s² 3p¹

c) 1s22s22p63s23p3

d) 3s² 3p⁵

e) 3s2

f) 1s22s22p63s23p2

g) 1s22s22p63s23p4

h) 3s² 3p⁶

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3 years ago

What is the [H+] and [OH-] of a 3.5 M HCIO3 solution?

levacccp [35]

Answer: H+ ia helyuim

explinanation: Hope this helped!!

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2 years ago

2. The most recent ice age ended about

zloy xaker [14]

Answer:

The most recent ice age ended about 10,000 years ago

Explanation:

The last ice age began 110,000 years ago and ended 10,000 years ago, leading to the temperature of the Earth, expansions of glaciers and polar ice caps were made.

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3 years ago

A student plans to use a density versus solution concentration standard curve to identify the sodium chloride concentration in a

Art [367]

Answer:

a. 0.50 g, 1.0 g, 1.5 g, 2.0 g, 2.5 g;

g. 0.1 g, 0.5 g, 1.0 g, 1.5 g, 2.0 g

Explanation:

The percent mass is defined as a ratio between the mass of a solute and mass of a solution:

$\omega = \frac{m_{solute}}{m_{solution}}\cdot 100\%$

Since solution only consists of a solute and solvent, express its mass as:

$m_{solution} = m_{solute} + m_{solvent}$

Then:

$\omega = \frac{m_{solute}}{m_{solution}}\cdot 100\%=\frac{m_{solute}}{m_{solute} + m_{solvent}}$

Firstly, solve for how much mass is required to prepare 3.0 %. Let's say, we have x g of the solute:

$0.03 = \frac{x}{30.0 + x}\therefore x = 0.03(30.0 + x)$

$x = 0.90 + 0.03x$

$0.97x = 0.90\therefore x = 0.93 g$

Similarly, solve for 6.0 %, let's say, we have x g of the solute again:

$0.06 = \frac{x}{30.0 + x}\therefore x = 0.06(30.0 + x)$

$x = 1.80 + 0.06x$

$0.94x = 1.80\therefore x = 1.91 g$

Hence, masses should be in a range of 0.93 g to 1.91 g.

7 0

3 years ago