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3 years ago

How many grams of mgo are produced when 40.0 grams of o2 react completely with mg? 2 mg (s) + o2 (g) → 2 mgo (s)?

Chemistry

1 answer:

SSSSS [86.1K]3 years ago

8 0

Answer: -

100 grams

Explanation: -

Mass of Oxygen = 40 g

Chemical formula of oxygen gas = O2

Molar mass of oxygen = 16 x 2 = 32 gram

Atomic mass of Mg = 24g

Molar mass of MgO = 24 x 1 + 16 x 1 =40 gram

The balanced chemical equation for the reaction is

2Mg + O2 -- > 2 MgO

So from the balanced equation we see that 1 O2 react to give 2 MgO

32 grams of O2 react to give 2 x 40 gram of MgO

40 grams of O2 react to give $\frac{2 x 40 gram x 40 gram}{32 gram}$

=100 gram of MgO

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3 years ago

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For methanol: Heat of combustion = -22.6 kJ / 0.0312 moles = -724.3590 kJ/mol (negative sign signifies release of heat)

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Explanation:

Given:

Mass of Methanol = 1.0 g

Mass of ethanol = 1.00 g

Mass of n-propanol = 1.00 g

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2 CH₃OH + 3 O₂ ----> 2 CO₂ + 4 H₂O, ∆H₀ = -22.6 kJ/g (negative sign signifies release of heat)

1 g of methanol on combustion gives 22.6 kJ of energy

Calculation of moles of methanol:

$moles=\frac{Mass(m)}{Molar\ mass (M)}$

Molar mass of methanol = 32.04 g/mol

Thus moles of methanol = 1 g/ (32.04 g/mol) = 0.0312 moles

Hence energy in kJ/mol:

Heat of combustion = -22.6 kJ / 0.0312 moles = -724.3590 kJ/mol (negative sign signifies release of heat)

For ethanol:

C₂H₅OH + 3 O₂ ----> 2 CO₂ + 3 H₂O, ∆H₀ = -29.7 kJ/g (negative sign signifies release of heat)

1 g of ethanol on combustion gives 29.7 kJ of energy

Calculation of moles of ethanol:

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Thus moles of ethanol = 1 g/ (46.07 g/mol) = 0.0217 moles

Hence energy in kJ/mol:

Heat of combustion = -29.7 kJ / 0.0217 moles = -1368.6636 kJ/mol (negative sign signifies release of heat)

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Heat of combustion = -33.4 kJ / 0.0166 moles = -2012.0482 kJ/mol (negative sign signifies release of heat)

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