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3 years ago

3 times the sum of x and y squared plus 5 times the difference of 2x and y

1 answer:

8 0

3x + xy^2 + 5x - 2xy ok so once you can decode the sentence this is what it will look like. First you add the common facts which are 3x and 5x which = 8x ok so now we have 8x + xy^2 - 2xy so then I believe you cant do anything after that because there will be no more common factors hey can you tell me if I am write if you have already had turn this in please hope this helps

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The power P produced by a wind turbine is directly proportional to the cube of the wind speed S. A wind speed of 37 miles per ho

vfiekz [6]

Answer:the output for a wind speed of 40 miles per hour is 810.8 kilowatts.

Step-by-step explanation:

The power P produced by a wind turbine is directly proportional to the cube of the wind speed S. This means that

P is directly proportional to S

Introducing a constant of proportionality, k, it becomes

P = kS

A wind speed of 37 miles per hour produces a power output of 750 kilowatts. This means that

750 = k × 37

k = 750/37 = 20.27

The expression becomes

P = 20.27S

Therefore, the output for a wind speed of 40 miles per hour would be

P = 20.27 × 40

P = 810.8

6 0

3 years ago

Can somebody help me solve for x?

Dahasolnce [82]

Let y = the distance between the top left corner and the bottom right corner

y^2 = 24^2 + 15^2

y^2 = 801

y = 3 * sqrt(89)

Now we can find x.

12^2 + x^2 = (3 * sqrt(89))^2

x^2 = 657

x = 3 * sqrt(73) or 25.63

7 0

3 years ago

Evaluate the definite integral using the graph of f(x)<br> (Image included)

Tanya [424]

a) The first integral corresponds to the area under y = f(x) on the interval [0, 3], which is a right triangle with base 3 and height 5, hence the integral is

$\displaystyle \int_0^3 f(x) \, dx = \frac12 \times 3 \times 5 = \boxed{\frac{15}2}$

b) The integral is zero since the areas under the curve over [3, 4] and [4, 5] are equal but opposite in sign. In other words, on the interval [3, 5], f(x) is symmetric and odd about x = 4, so

$\displaystyle \int_3^5 f(x) \, dx = \int_3^4 f(x) \, dx + \int_4^5 f(x) \, dx = \int_3^4 f(x) \, dx - \int_3^4 f(x) \, dx = \boxed{0}$

c) The integral over [5, 9] is the negative of the area of a rectangle with length 9 - 5 = 4 and height 5, so

$\displaystyle \int_5^9 f(x) \, dx = -4\times5 = -20$

Then by linearity, we have

$\displaystyle \int_0^9 f(x) \, dx = \left\{\int_0^3 + \int_3^5 + \int_5^9\right\} f(x) \, dx = \frac{15}2 + 0 - 20 = \boxed{-\frac{25}2}$

8 0

2 years ago

Did i do this right?

Amanda [17]

Answer:

yes

Step-by-step explanation:

3 0

1 year ago

“Drew has 50 red, green, and blue marbles. He has six more red marbles than blue marbles and four fewer green marbles than blue

kolezko [41]

(1) R+G+B=50
(2) R=B+6
(3) G=B-4 so substitute G in (1)
R+B-4+B=50 substitute (2) in here
B+6+B-4+B=50 group like terms and solve
3B+2=50
3B=50-2
B=48/3=16 substitute in (2) and (3)
R=16+6=22
G=16-4=12
Check
22+12+16=50✅

8 0

3 years ago