Answer:
See explanation
Explanation:
The boiling point of a substance is affected by the nature of bonding in the molecule as well as the nature of intermolecular forces between molecules of the substance.
2-methylpropane has only pure covalent and nonpolar C-C and C-H bonds. As a result of this, the molecule is nonpolar and the only intermolecular forces present are weak dispersion forces. Therefore, 2-methylpropane has a very low boiling point.
As for 2-iodo-2-methylpropane, there is a polar C-I bond. This now implies that the intermolecular forces present are both dispersion forces and dipole interaction. As a result of the presence of stronger dipole interaction between 2-iodo-2-methylpropane molecules, the compound has a higher boiling point than 2-methylpropane.
Answer:
B. It is formed by a repeating pattern of a single type of atom
Explanation:
i think thats answer may i get brainlest?
The ranges given are 4 × 10^14 to 7.5 × 10^14 Hz. At these frequencies, visible light type of waves are found in this region. This occurs at a wavelength of 400 - 700 nanometers and a color of violet through red. Outside this range, the naked eye cannot see the waves.
1000 liters = 1 m^3
and
1.3um^3 = 1.3x10^(-6)m^3
multiply both sides of the first equation by 1.3x10^(-6)
1.3x10^(-6) * 1000 liters = 1.3x10^(-6) * 1m^3
1.3x10^(-3) liters = 1.3x10^(-6) m^3
