Ten Seconds after starting from rest, a car moving at 40 m/s what is the cars average acceleration

Which two factors determine the amount of work done?

nignag [31]

Distance and force.
You need to know how much force was needed and how far it went to calculate how much work was done. The answer is C.

5 0

4 years ago

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What tools enable people to connect and exchange ideas

aleksklad [387]

Answer:

The answer is: "Social Media tools"

Explanation:

"Social Media tools" are very popular tools being used by the modern generation these days. They come in different types according to their usage (Listening Platforms, Publishing Platforms and Competitive Analysis Platforms). Examples of these are: Hootsuite, Buffer, Oktopost, Canva, Google Trends, BuzzSumo, etc.

These tools allow people to interact with one another. People can published the information they want to share and distribute this information to other people. Marketers also use these tools in order to aid them regarding online businesses and the like. Some social media tools are available for free while others have to be purchased.

Thus, this explains the answer.

5 0

4 years ago

Which of the following is an example of refraction?

Sladkaya [172]

I believe it will be C.

7 0

3 years ago

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Two identical conducting spheres, fixed in place, attract each other with an electrostatic force of -0.9537 N when separated by

scoray [572]

Answer:

The initial charges on the spheres are $6.796\ 10^{-6}\ c$ and $-3.898\ 10^{-6}\ c$

Explanation:

Electrostatic Force

Two charges q1 and q2 separated a distance d exert a force on each other which magnitude is computed by the known Coulomb's formula

$\displaystyle F=\frac{K\ q_1\ q_2}{d^2}$

We are given the distance between two unknown charges d=50 cm = 0.5 m and the attractive force of -0.9537 N. This means both charges are opposite signs.

With these conditions we set the equation

$\displaystyle F_1=\frac{K\ q_1\ q_2}{0.5^2}=-0.9537$

Rearranging

$\displaystyle q_1\ q_2=\frac{-0.9537(0.5)^2}{k}$

Solving for q1.q2

$\displaystyle q_1\ q_2=-2.6492.10^{-11}\ c^2\ \ ......[1]$

The second part of the problem states the spheres are later connected by a conducting wire which is removed, and then, the spheres repel each other with an electrostatic force of 0.0756 N.

The conducting wire makes the charges on both spheres to balance, i.e. free electrons of the negative charge pass to the positive charge and they finally have the same charge:

$\displaystyle q=\frac{q_1+q_2}{2}$

Using this second condition:

$\displaystyle F_2=\frac{K\ q^2}{0.5^2}=\frac{K(q_1+q_2)^2}{(4)0.5^2}=0.0756$

$\displaystyle q_1+q_2=2.8983\ 10^{-6}\ C$

Solving for q2

$\displaystyle q_2=2.8983\ 10^{-6}\ C-q_1$

Replacing in [1]

$\displaystyle q_1(2.8983\ 10^{-6}-q_1)=-2.64917.10^{-11}$

Rearranging, we have a second-degree equation for q1.

$\displaystyle q_1^2-2.8983.10^{-6}q_1-2.64917.10^{-11}=0$

Solving, we have two possible solutions

$\displaystyle q_1=6,796.10^{-6}\ c$

$\displaystyle q_1=-3.898.10^{-6}\ c$

Which yields to two solutions for q2

$\displaystyle q_2=-3.898.10^{-6}\ c$

$\displaystyle q_2=6.796.10^{-6}\ c$

Regardless of their order, the initial charges on the spheres are $6.796\ 10^{-6}\ c$ and $-3.898\ 10^{-6}\ c$

8 0

3 years ago

Various singly-ionized atomic nuclei of the same speed are directed into a magnetic field in a mass spectrometerwhere they are d

ki77a [65]

Answer:

a) least mass

Explanation:

According to the Newton's first law of motion, more the mass of a body the greater is its inertia, and inertia is the tendency of a body to resist any change to its state of rest or uniform motion.

Greater is the mass of charge least is its deflection under the influence of magnetic field.

This can be explained well by the mathematical equations relating the centripetal force and the magnetic force on a charged mass moving in a magnetic field perpendicular to the velocity:

$m.\frac{v^2}{r} =q.v.B$

where:

m = mass of the charged particle

v = velocity of projection of the charged mass into the magnetic field

r = radius of curvature of path of charged mass under the magnetic force

q = magnitude of charge on the particle of mass 'm'

B = intensity of magnetic field normal to 'v'

$\Rightarrow v=\frac{q.B.r}{m}$

$\Rightarrow v\propto \frac{1}{m}$

i.e.

Speed of the charge is higher when its mass is lesser and according to the Fleming's left hand rule we known that the charge continuously faces a magnetic force while moving in the field.

& also,

$\Rightarrow m\propto \frac{1}{r}$

Which indicates that more is the mass of charge larger is the radius of its trajectory of motion which means lesser is its deviation.

6 0

4 years ago