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Cerrena [4.2K]
3 years ago
11

Each of 7 students reported the number of movies they saw in the past year. Here is what they reported. 16,17,17,13,9,7,4 find t

he mean number of movies that the students saw
Chemistry
1 answer:
mixer [17]3 years ago
4 0
The answer is 11.85 but rounds up to 12
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Consider the Zn(s) + Cu^+2(aq) --->Zn^+2(aq) + Cu(s) system. Which element was the electron donor?
Tpy6a [65]
Basically, electron donors are the elements that give up there electrons, so they will be oxidized. In the reaction, Zn(s) oxidizes into Zn^+2, so the 2 electrons are bing donated to the Cu^2+. Thus Zn(s) is the electron donor
3 0
3 years ago
In the event that a chemical gets in your eye while in the lab, you would use the eyewash station. In your at-home lab, however,
kozerog [31]

Answer:

Using the sprayer on your sink if you have one

Explanation:

If a chemical gets into your eye, you will need to flush the eye thoroughly with water in order to get the chemical out of the eye before it causes any kind of damage to the eye.

This could normally be done in an eye wash station. However in the absence of an eye wash station, one could use the sprayer of the sink if he/she has one. This will deliver water to completely flush the eye at lower pressure.

7 0
2 years ago
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An atom can be neutral when there a same amount of protons and electrons
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3 years ago
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Anettt [7]

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6 0
3 years ago
if a gas sample has a pressure of 761 mmhg at 0.00°c by how much does the temperature have to decrease to lower the pressure to
Nady [450]
<h3>Answer:</h3>

272.43 K or -0.718°C

<h3>Explanation:</h3>

We are given;

The initial pressure,P1 as 761 mmHg

Initial temperature, T1 as 0.00°C which is equivalent to 273.15 K

Final pressure as 759 mmHg

We are required to calculate the final temperature;

According to pressure law, the pressure of a gas and absolute temperature are directly proportional at constant volume.

That is; Pα T

Therefore, at varying pressure and temperature,

\frac{P1}{T1}=\frac{P2}{T2}

To get final temperature;

T2=\frac{P2T1}{P1}

T2=\frac{(759 mmHg)(273.15K)}{761 mmHg}

T2=272.43K

Therefore, the final temperature will be 272.43 K or -0.718°C

6 0
3 years ago
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