Ask question

Ask question

All categories

3 years ago

11

Each of 7 students reported the number of movies they saw in the past year. Here is what they reported. 16,17,17,13,9,7,4 find t

he mean number of movies that the students saw

1 answer:

mixer [17]3 years ago

4 0

The answer is 11.85 but rounds up to 12

You might be interested in

List the Earth names for the 30 alien elements in order of atomic number

mariarad [96]

Pfsst
bombal
chow
ddoggone
ernst
floxxit
goldy
nuutye
apstrom
logon
byyou
zapper
yazzer
highho
magnificon
oz
fratt
jeptum
quackzil
doadeer
rhaap
terriblum
sississ
urrp
vulcania
wobble
xtalt
pie
anatom
eldorado (I think these are the answers)

6 0

3 years ago

Why can more sugar be dissolved in hot water than cold water (more solute be dissolved in hot solvent then cold solvent)

lesantik [10]

Sugar dissolves faster in hot water than it does in cold water because hot water has more energy than cold water. when water is heated, the molecules gain energy and because of that, move faster. as they move faster, they come in contact with the sugar more often, causing it to dissolve faster.

4 0

3 years ago

If an atom has an atomic number of 6 and and abdomens mass of 12 how many electrons does it have

Basile [38]

Atomic number refers to the proton number of the atom itself. Number of electrons in an atom (an atom that is not reacted with any other molecules / Just the atom alone), is the same as the number of protons, because each electron has 1 negative charge, and each proton 1 positive charge, where they cancel out on each other to become a neutral charge.

So, when atomic number is 6, proton number is also 6, and number of electrons will also be 6 in that atom.

Hope this helps! :)

5 0

3 years ago

How many moles of KOH are required to produce 4.79 g K3PO4 according to the following reaction? 3KOH + H3PO4 -----> K3PO4 + 3

8_murik_8 [283]

Answer:

0.677 moles

Explanation:

Take the atomic mass of K = 39.1, O =16.0, P = 31.0

no. of moles = mass / molar mass

no. of moles of K3PO4 used = 4.79 / (39.1x3 + 31 + 16x4)

= 0.02256 mol

From the equation, the mole ratio of KOH : K3PO4 = 3 :1,

meaning every 3 moles of KOH used, produces 1 mole of K3PO4.

So, using this ratio, let the no. of moles of KOH required to be y.

$\frac{3}{1} =\frac{y}{0.02256} \\$

y = 0.02256 x3

y = 0.0677 mol

If you don't find exactly 0.677 moles as one of the options, go for the closest one. A very slight error may occur because of taking different significant figures of atomic masses when calculating.

5 0

3 years ago

Consider the second-order reaction:

kirza4 [7]

Answer:

Initial concentration of HI is 5 mol/L.

The concentration of HI after $4.53\times 10^{10} s$ is 0.00345 mol/L.

Explanation:

$2HI(g)\rightarrow H_2(g)+I_2(g)
$

Rate Law: $k[HI]^2
$

Rate constant of the reaction = k = $6.4\times 10^{-9} L/mol s$

Order of the reaction = 2

Initial rate of reaction = $R=1.6\times 10^{-7} Mol/L s$

Initial concentration of HI = $[A_o]$

$1.6\times 10^{-7} mol/L s=(6.4\times 10^{-9} L/mol s)[HI]^2$

$[A_o]=5 mol/L$

Final concentration of HI after t = [A]

t = $4.53\times 10^{10} s$

Integrated rate law for second order kinetics is given by:

$\frac{1}{[A]}=kt+\frac{1}{[A_o]}$

$\frac{1}{[A]}=6.4\times 10^{-9} L/mol s\times 4.53\times 10^{10} s+\frac{1}{[5 mol/L]}$

$[A]=0.00345 mol/L$

The concentration of HI after $4.53\times 10^{10} s$ is 0.00345 mol/L.

5 0

3 years ago