Answer:
7923.6 g of (NH₄)₂SO₄ can be produced by this reaction
Explanation:
The reaction is:
2NH₃ (aq) + H₂SO₄(aq) → (NH₄)₂SO₄(aq)
In this reaction ratio is 1:1.
As the ammonia is in excess, the limiting reagent is the sulfuric acid.
So 1 mol of sulfuric can produce 1 mol of sulfate
Then, 60 moles of sulfuric must produce 60 moles of sulfate.
We convert the moles to mass:
60 mol . 132.06 g / 1mol = 7923.6 g
Collide is the correct answer
Answer
is: Ksp for AB₂ is 2.06·10⁻¹⁰.<span>
Chemical reaction: AB</span>₂(s) → Aˣ⁺(aq) + 2Bⁿ⁻(aq).
<span>
s(AB</span><span>₂) =
3,72·10⁻⁴ M.</span><span>
s(AB</span>₂) =
s(Aˣ⁺).
s(Bⁿ⁻) =
2s(AB₂).
Ksp(AB₂) = s(Aˣ⁺) ·
(s(Bⁿ⁻))².<span>
Ksp</span>(AB₂) = 3,72·10⁻⁴ ·
(7,44·10⁻⁴)².
Ksp(AB₂)= 2,06·10⁻¹⁰.
The term sulfate is used in chemistry to denote a salt of sulfuric acid. ... This is the sulfate type which can be found in many cleaning and hygiene products including shampoos. The main reasons why it is added to shampoos are because this sulfate produces foam and is a powerful detergent.
It's likely what's wanted is
<span><span>Li</span>→<span><span>Li</span><span>2+</span></span>+2<span>e−
</span></span>
The reason is because IEs are usually reported from the neutral atom, that is, IE2 is the energy required to remove two electrons from a neutral Li atom, as above, rather than the additional energy required to remove one more electron from an Li+ cation.