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Feliz [49]
3 years ago
8

What is the mass for 3.01*10 23 molecules h2o

Chemistry
2 answers:
Genrish500 [490]3 years ago
7 0
<em>M H₂O: 1g×2 + 16g = 18g
</em>

6,02×10²³ --------- 18g
3,01×10²³ --------- Xg
X = (18×3,01×10²³)/<span>6,02×10²³
<u>X = 9g

</u>:)
</span>
hoa [83]3 years ago
3 0

Answer:

The answer is 8.99 g of water

Explanation:

First we calculate the molecular mass of water, as follows. using the periodic table we have the masses of hydrogen and oxygen:

MW of H2 2 x 1 g/mol=2g/mol

MW of O: 16 g/mol

MW of H2O=2+16=18 g/mol

using Avogadro's number and making a simple direct rule of three we have:

6.023x10^{23}mol----------------------18 g

3.01x10^{23} mol------------------------ Xg

Clearing the X, we have:

X = \frac{18 g x 3.01x10^{23}mol }{6.023x10x^{23} mol}=8.99 g of water

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When you combine chocolate powder and milk, the result is best describe as?
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3 0
3 years ago
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f 23.6 mL of 0.200 M NaOH is required to neutralize 10.00 mL of a H3PO4 solution , what is the concentration of the phosphoric a
Eduardwww [97]

Answer:

Explanation:

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= 0.00472mole

let x be the no of mole of H3PO4 required of  0.00472mole of NaOH

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<h3>The concentration of unknown phosphoric acid is  0.157M</h3>
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3 years ago
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