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Feliz [49]
3 years ago
8

What is the mass for 3.01*10 23 molecules h2o

Chemistry
2 answers:
Genrish500 [490]3 years ago
7 0
<em>M H₂O: 1g×2 + 16g = 18g
</em>

6,02×10²³ --------- 18g
3,01×10²³ --------- Xg
X = (18×3,01×10²³)/<span>6,02×10²³
<u>X = 9g

</u>:)
</span>
hoa [83]3 years ago
3 0

Answer:

The answer is 8.99 g of water

Explanation:

First we calculate the molecular mass of water, as follows. using the periodic table we have the masses of hydrogen and oxygen:

MW of H2 2 x 1 g/mol=2g/mol

MW of O: 16 g/mol

MW of H2O=2+16=18 g/mol

using Avogadro's number and making a simple direct rule of three we have:

6.023x10^{23}mol----------------------18 g

3.01x10^{23} mol------------------------ Xg

Clearing the X, we have:

X = \frac{18 g x 3.01x10^{23}mol }{6.023x10x^{23} mol}=8.99 g of water

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Be sure to answer all parts. A concentration cell consists of two Sn/Sn2+ half-cells. The electrolyte in compartment A is 0.23 M
kolbaska11 [484]

Answer:

Part A. The half-cell B is the cathode and the half-cell A is the anode

Part B. 0.017V

Explanation:

Part A

The electrons must go from the anode to the cathode. At the anode oxidation takes place, and at the cathode a reduction, so the flow of electrons must go from the less concentrated solution to the most one (at oxidation the concentration intends to increase, and at the reduction, the concentration intends to decrease).

So, the half-cell B is the cathode and the half-cell A is the anode.

Part B

By the Nersnt equation:

E°cell = E° - (0.0592/n)*log[anode]/[cathode]

Where n is the number of electrons being changed in the reaction, in this case, n = 2 (Sn goes from S⁺²). Because the half-reactions are the same, the reduction potential of the anode is equal to the cathode, and E° = 0 V.

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3 0
3 years ago
The thermite reaction reacts iron (III) oxide, Fe2O3, with aluminium powder,Al, the form aluminium oxide, Al2O3 and iron, Fe.
lara [203]

Answer:

<u><em>This answer assumes that the strated "16.0g of iron" was meant to be 16.0 grams of iron(III) oxide.</em></u>

Explanation:

To start, the thermite equation must be balanced.

I find:

1Fe2O3 + 2Al = 1Al2O3 + 2Fe

This tells us we need 2 moles of Al for every 1 mole of Fe2O3.  

Now calculate the moles of each reactant:

Moles Fe2O3:  16.0 g/159.7 g/mole = <u>0.100 moles Fe2O3</u>

Moles Al:  8.1 /26.98 g/mole = <u>0.300 moles Al</u>

The balanced equation says that in order to react all of the Fe2O3 we'd need twice that amount (in moles) of the Al.  (0.100 moles Fe2O3)*(2) = 0.200 moles Al.

<u>Which of the two reactants is the limiting reagent?</u>

We have more than enough moles of Al to react with 0.10 moles of Fe2O3.  (We have 0.300 moles Al and all we need is 0.200 moles to react with the 0.10 moles of Fe2O3.  <em>Fe2O3 is the limiting reagent.</em>

<u><em>Calculate the maximum mass of iron of iron that could be formed using these quantities of reactants.</em></u>

The balanced equation tells us that we will obtain 2 moles of Fe for every 1 mole of Fe2O3 consumed.  Since Fe2O3 is the limiting reagent, we will assume that it completely reacts.  That means 0.1 moles of Fe2O3 is reacted.  Since we expect twice that many moles of Fe, we should obtain 0.200 moles of Fe.  At 55.85 g/mole, we should obtain:

(0.200 moles Fe)*(55.85 g Fe/mole Fe) = 11.2 grams Fe

<em></em>

<em></em>

5 0
2 years ago
How can we tell when something is polar or non-polar in an Inter-molecular Force?
Montano1993 [528]
If the substance mixes with water it's polar. If it doesn't it ms non polar.
7 0
3 years ago
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