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earnstyle [38]
3 years ago
14

David is driving a steady 30.0 m/s when he passes Tina, who is sitting in her car at rest. Tina begins to accelerate at a steady

2.10 m/s2 at the instant when David passes. Part A How far does Tina drive before passing David
Physics
2 answers:
SpyIntel [72]3 years ago
7 0

Answer:

Explanation:

Let after time t , Tina catches up David .

Distance travelled by them are equal ,

Distance travelled by Tina

s = ut + 1/2 a t²

= .5 x 2.10 t²

= 1.05 t²

Distance travelled by David

= 30 t ( because of uniform velocity )

1.05 t² = 30t

t = 28.57 s

Distance travelled by Tina

= 1/2 a t²

= .5 x 2.10 x 28.57²

= 857 m approx.

nikklg [1K]3 years ago
5 0

Answer: 857\ m

Explanation:

Given

Speed of David car v=30\ m/s

Tina begins to accelerate 2.1\ m/s^2 after David pass the tina

Suppose it took t time for tina to catch David

Distance traveled by David in t time

\Rightarrow s_d=30\times t

Using the equation of motion to get the distance of Tina is

s_t=ut+\dfrac{1}{2}at^2\\\\s_t=0+\dfrac{1}{2}\times 2.1t^2

now, s_d=s_t

30t=\dfrac{2.1}{2}t^2\\\\\Rightarrow 2.1t^2-60t=0\\\Rightarrow t(2.1t-60)=0\\\Rightarrow t=0,28.57\ s

Neglecting t=0

Distance traveled by tina in 28.57\ s is

s_t=\dfrac{1}{2}\times 2.1\times (28.57)^2\\\\s_t=857.057\approx 857\ m

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A car drives 90 meters north, then turns around and drives 120 meters south. What was its displacement and distance?
Rufina [12.5K]

Answer:

displacement= 30 m towards south, distance= 210m

Explanation:

Distance (scalar quantity) how much ground an object has covered.

Displacement (vector quantity) refers to how far out of place an object is it is the object's overall change in position.

Basically meaning for displacement the directions will be very key

D for Displacement

D= D1+D2

D=  120 (S) + 90 m (N)

Must be in same direction

D= 120 (S) + (-90 m) (S)

D= 30 m (S)

and for distance you are simply just adding how much distance they have covered

so d= d1+d2

d= 90m + 120m

d= 210m

3 0
2 years ago
If 2 grams of element X combine with 4 grams of element Y to form compound XY, how many grams of element Y would combine with 46
Butoxors [25]
92 grams of Y would combine with 46 grams of X
3 0
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Paheli observed the shadow of a tree at 8:00 a.m., 12:00 noon
Anika [276]
Both the size and the shape of the tree changes
6 0
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Read 2 more answers
a hippopotamus produces a pressure of 250000 pa when it is standing on all four feet if the weight of the hippo is 40000 N what
mamaluj [8]

0.04m²

Explanation:

Given parameters:

Pressure = 250000Pa

Weight = 40000N

Unknown:

Area of each foot = ?

Solution:

Pressure is the force exerted per unit area of a body

  Pressure = \frac{force}{area}

To find the area;

        Area = \frac{force }{pressure}

    Area = \frac{40000}{250000} = 0.16m²

The force exerted by all the four feet is 0.16m²

the area of each feet = \frac{0.16}{4} = 0.04m²

Learn more:

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8 0
3 years ago
An interference pattern is produced by light with a wavelength 520 nm from a distant source incident on two identical parallel s
Goshia [24]

Answer:

1) θ = 0.00118 rad, 2)  θ = 0.00236 rad , 3) I / I₀ = 0.1738, 4)  I / Io = 0.216

Explanation:

In the double-slit interference phenomenon it is explained for constructive interference by the equation

          d sin θ = m λ

1) the first order maximum occurs for m = 1

           sin θ = λ  / d

           θ = sin⁻¹ λ  / d

let's reduce the magnitudes to the SI system

           λ  = 520 nm = 520 10⁻⁹  θ = 0.00118 radm

           d = 0.440 mm = 0.440 10⁻³ m ³

let's calculate

           θ = sin⁻¹ (520 10⁻⁹ / 0.44 10⁻³)

            θ = sin⁻¹ (1.18 10⁻³)

            θ = 0.00118 rad

2) the second order maximum occurs for m = 2

            θ = sin⁻¹ (m λ  / d)

            θ = sin⁻¹ (2 5¹20 10⁻⁹ / 0.44 10⁻³)

            θ = 0.00236 rad

3) To calculate the intensity of the interference spectrum, the diffraction phenomenon must be included, so the equation remains

          I = I₀ cos² (π d sin θ /λ ) sinc² (pi b sin θ /λ )

where the function sinc = sin x / x

and b is the width of the slits

we caption the values

             x = π 0.310 10⁻³ sin 0.00118 / 520 10⁻⁹)

             x = 2.21

            I / I₀ = cos² (π 0.44 10⁻³ sin 0.00118 / 520 10⁻⁹) (sin (2.21) /2.21)²

remember angles are in radians

            I / I₀ = cos² (3.0945) [0.363] 2

            I / I₀ = 0.9978 0.1318

            I / I₀ = 0.1738

4) the maximum second intensity is

            I / I₀ = cos² (π d sinθ / λ) sinc² (πb sin θ /λ)

            x =π 0.310 10⁻³ sin 0.00236 / 520 10⁻⁹)

            x = 4.41

            I / Io = cos² (π 0.44 10⁻³ sin 0.00236 / 520 10⁻⁹) (sin 4.41 / 4.41)²

            I / Io = cos² 6.273    0.216

            I / Io = 0.216

.

7 0
3 years ago
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