Answer:
94.28 inches/second.
Step-by-step explanation:
The length of the circumference of the circular path with 10 inches radius is = 
inches.
Now, the point on the edge of the wheel moves by 3 revolutions in 2 seconds.
So, in 2 seconds the point moves a linear distance of (3 × 62.85) = 188.57 inches.
Therefore, the linear velocity of the point in inches per second is 
inches per second.
(Answer)
The sum of angles of a triangle is 180°, so m∠K = 180° -45° -30° = 105°.
The Law of Sines tells you
... FL/sin(∠K) = FK/sin(∠L)
Solving for FL, we get
... FL = FK·sin(∠K)/sin(∠L)
... FL = a·sin(105°)/sin(30°) = a·sin(105°)/(1/2)
... FL = 2a·sin(105°) ≈ 1.93185a
Answer:
Step-by-step explanation:
-1/4(-8x+12y)
-1*(-8x+12y)/4
8x-12y/4
4(2x-3y)/4(4 and 4 gets cancel)
2x-3y
<span>8x^2-50
= 2(4x^2 - 25)
= 2(2x + 5)(2x - 5)
hope it helps</span>
Answer: y = 2.5(x-1)
Step-by-step explanation:
Step 1
Find the point of tangency.
It's given as (x,y)= (1,0)
Step 2
Find the first derivative, and evaluate it at x=1
f'(x) = 5/2 × d(lnx)/dx = 5/2 × 1/x = 5/2x
f'(x) = 5/2 = 2.5
The slope of the tangent line at this point is m= 2.5
Step 3
Find the equation of the tangent line at (1,0) with a slope of m=2.5
y−y1 = m(x - x1)
y-0 = 2.5(x-1)
y = 2.5(x-1)
