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muminat
3 years ago
11

Please help. I don’t understand any of this.

Mathematics
2 answers:
STatiana [176]3 years ago
4 0
If the two triangles are congruent (not just similar), then QS and TV would be equal.  Thus, 3v + 2 = 7v - 6.

Solving this equation for v:  4v = 8, and v = 2.

Then QS = 3(2) + 2, or 8, and TV should be the same:  7(2) - 6 = 8.
aniked [119]3 years ago
4 0

Answer:

If the two triangles are congruent (not just similar), then QS and TV would be equal.  Thus, 3v + 2 = 7v - 6.

Solving this equation for v:  4v = 8, and v = 2.

Then QS = 3(2) + 2, or 8, and TV should be the same:  7(2) - 6 = 8.

Step-by-step explanation:

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Which set of numbers could be the length of the sides of a triangle?
san4es73 [151]

3. {6,9,15)

for these u have use Pythagoras theorem

4 0
3 years ago
Help plz!!!!!!!!!!!!!
trapecia [35]

Answer:

i believe the relative max coordinate is (2,4)

relative min is (-2,0) and (4,0)

and these are not absolute exterma maybe because there are more than one relative min?

6 0
2 years ago
Considering only the values of β for which sinβtanβsecβcotβ is defined, which of the following expressions is equivalent to sinβ
-Dominant- [34]

Answer:

\tan(\beta)

Step-by-step explanation:

For many of these identities, it is helpful to convert everything to sine and cosine, see what cancels, and then work to build out to something.  If you have options that you're building toward, aim toward one of them.

{\tan(\theta)}={\dfrac{\sin(\theta)}{\cos(\theta)}    and   {\sec(\theta)}={\dfrac{1}{\cos(\theta)}

Recall the following reciprocal identity:

\cot(\theta)=\dfrac{1}{\tan(\theta)}=\dfrac{1}{ \left ( \dfrac{\sin(\theta)}{\cos(\theta)} \right )} =\dfrac{\cos(\theta)}{\sin(\theta)}

So, the original expression can be written in terms of only sines and cosines:

\sin(\beta)\tan(\beta)\sec(\beta)\cot(\beta)

\sin(\beta) * \dfrac{\sin(\beta) }{\cos(\beta) } * \dfrac{1 }{\cos(\beta) } * \dfrac{\cos(\beta) } {\sin(\beta) }

\sin(\beta) * \dfrac{\sin(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}}{\cos(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}} * \dfrac{1 }{\cos(\beta) } * \dfrac{\cos(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}} {\sin(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}}

\sin(\beta) *\dfrac{1 }{\cos(\beta) }

\dfrac{\sin(\beta)}{\cos(\beta) }

Working toward one of the answers provided, this is the tangent function.


The one caveat is that the original expression also was undefined for values of beta that caused the sine function to be zero, whereas this simplified function is only undefined for values of beta where the cosine is equal to zero.  However, the questions states that we are only considering values for which the original expression is defined, so, excluding those values of beta, the original expression is equivalent to \tan(\beta).

8 0
2 years ago
Round each number to the nearest hundredth.
Nina [5.8K]
A. 8.75
B. 0.72
C. 9.31
D. 23.04
E. 6.98
5 0
3 years ago
Read 2 more answers
HELP FAST!!!<br><br> Find 78% of 380. Round to the nearest tenth if necessary.
bonufazy [111]
78% = 78 / 100 = 0.78

What is 78% of 380

= 78% * 380

= 0.78 * 380

= 296.4

U said I should round it up IF NECESSARY so yeah....


5 0
3 years ago
Read 2 more answers
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